Question

Складіть два молекулярних рівняння реакцій між речовинами, які у розчинах взаємодіють за такою схемою Zn2+ + 2OH─ → Zn(OH)2

Answer 1

ZnCl2 + 2NaOH=Zn(OH)2↓+2NaCl

ZnSO4 + 2KOH =Zn(OH)2↓ + K2SO4 

Answer 2

Molecular Equations for the Given Reaction Scheme

The given reaction scheme represents the reaction between substances in solution. The reaction involves the interaction of Zn^2+ ions and hydroxide ions (OH^-) to form zinc hydroxide (Zn(OH)2). To represent this reaction in the form of molecular equations, we can follow the steps below.

1. Write the Ionization Equations: - The first step is to write the ionization equations for the substances involved. This involves breaking down the compounds into their respective ions when they are in solution.

- For Zn^2+, it ionizes into Zn^2+ ions: ``` Zn^2+ (aq) → Zn^2+ (aq) ```

- For OH^-, it ionizes into hydroxide ions: ``` 2OH^- (aq) → 2OH^- (aq) ```

2. Combine the Ions to Form the Product: - The next step is to combine the ions to form the product, which in this case is zinc hydroxide (Zn(OH)2).

- The molecular equation for the formation of zinc hydroxide from Zn^2+ and OH^- ions is: ``` Zn^2+ (aq) + 2OH^- (aq) → Zn(OH)2 (s) ```

- It's important to note that the product is written as a solid (s) to indicate that it is not dissolved in the solution.

Conclusion

The molecular equations for the given reaction scheme involving the interaction of Zn^2+ ions and hydroxide ions to form zinc hydroxide are as follows: 1. Ionization equation for Zn^2+: Zn^2+ (aq) → Zn^2+ (aq) 2. Ionization equation for OH^-: 2OH^- (aq) → 2OH^- (aq) 3. Molecular equation for the formation of zinc hydroxide: Zn^2+ (aq) + 2OH^- (aq) → Zn(OH)2 (s)