Question

Помогите определить степень окисления следующих элементов: N2O, NO2, N2O3, NH3 KClO3, Na3PO4, ZnSiO3, Ag2CO3 Кто понимает тему объясните пожалуйста!!!!!!

Answer 1

N(+1)2O(-2), N(+4)O(-2)2, N(+3)2O(-2)3, N(-3)H(+)3
K(+)Cl(+5)O(-2)3, Na(+)3P(+5)O(-2)4, Zn(+2)Si(+4)O(-2)3, Ag(+)2C(+4)O(-2)3

Na3PO4
1) у натрия постоянная степень окисления +1
2) у кислорода -2
3) у фосфора( центральный атом) +Х
4) сумма степеней окисления в молекуле равна=0
5) составим уравнение ( умножаем степень окисления на кол-во атомов)
+1*3+Х*1+(-2)*4=0
3+х-8=0
х=5 это степень окисления фосфора

Answer 2

Determining Oxidation States of Elements

Determining the oxidation state, also known as the oxidation number, of an element in a compound involves assigning a hypothetical charge to the element based on a set of rules. Here are the oxidation states of the elements you mentioned:

1. N2O: In N2O, the oxidation state of oxygen (O) is typically -2. Since the compound is neutral, the sum of the oxidation states must be zero. Therefore, the oxidation state of nitrogen (N) can be calculated as follows: - Let x be the oxidation state of N. - The sum of the oxidation states is 0: 2x + (-2) = 0. - Solving the equation gives x = +1 for the oxidation state of N [[1]].

2. NO2: In NO2, the oxidation state of oxygen (O) is typically -2. Again, the sum of the oxidation states must be zero. Therefore, the oxidation state of nitrogen (N) can be calculated as follows: - Let x be the oxidation state of N. - The sum of the oxidation states is 0: x + 2(-2) = 0. - Solving the equation gives x = +4 for the oxidation state of N [[2]].

3. N2O3: In N2O3, the oxidation state of oxygen (O) is typically -2. The sum of the oxidation states must be zero. Therefore, the oxidation state of nitrogen (N) can be calculated as follows: - Let x be the oxidation state of N. - The sum of the oxidation states is 0: 2x + 3(-2) = 0. - Solving the equation gives x = +3 for the oxidation state of N [[3]].

4. NH3: In NH3, the oxidation state of hydrogen (H) is typically +1. The sum of the oxidation states must be zero. Therefore, the oxidation state of nitrogen (N) can be calculated as follows: - Let x be the oxidation state of N. - The sum of the oxidation states is 0: x + 3(+1) = 0. - Solving the equation gives x = -3 for the oxidation state of N [[4]].

5. KClO3: In KClO3, the oxidation state of oxygen (O) is typically -2. The sum of the oxidation states must be zero. Therefore, the oxidation state of chlorine (Cl) can be calculated as follows: - Let x be the oxidation state of Cl. - The sum of the oxidation states is 0: (+1) + x + 3(-2) = 0. - Solving the equation gives x = +5 for the oxidation state of Cl [[5]].

6. Na3PO4: In Na3PO4, the oxidation state of oxygen (O) is typically -2. The sum of the oxidation states must be zero. Therefore, the oxidation state of phosphorus (P) can be calculated as follows: - Let x be the oxidation state of P. - The sum of the oxidation states is 0: 3(+1) + 4(-2) + x = 0. - Solving the equation gives x = +5 for the oxidation state of P [[6]].

7. ZnSiO3: In ZnSiO3, the oxidation state of oxygen (O) is typically -2. The sum of the oxidation states must be zero. Therefore, the oxidation state of zinc (Zn) and silicon (Si) can be calculated as follows: - Let x be the oxidation state of Zn and y be the oxidation state of Si. - The sum of the oxidation states is 0: x + y + 3(-2) = 0. - Solving the equation gives x = +2 for the oxidation state of Zn and y = +4 for the oxidation state of Si [[7]].

8. Ag2CO3: In Ag2CO3, the oxidation state of oxygen (O) is typically -2. The sum of the oxidation states must be zero. Therefore, the oxidation state of silver (Ag) and carbon (C) can be calculated as follows: - Let x be the oxidation state of Ag and y be the oxidation state of C. - The sum of the oxidation states is 0: 2x + y + 3(-2) = 0. - Solving the equation gives x = +1 for the oxidation state of Ag and y = +4 for the oxidation state of C [[8]].

I hope this helps! Let me know if you have any further questions.