Question

1)FeCI3 + NaOH → Fe (OH)3↓ + ... 2)Fe (OH)3 + H2SO4 → Fe2 (SO4)3 + ... 3) Cu (OH)2 ↓ + NaOH →… 4)Al2(SO4)3 + NaOH → ... 5) All (OH)3 + H2SO4 →... 6) Al (OH)3 + NaOH →...

Answer 1

FeCl3 + 3 NaOH = Fe(OH)3 ↓+ 3 NaCl
3H2SO4 + 2Fe(OH)3 = Fe2(SO4)3 + 6H2O 
Cu(OH)2 + 2NaOH = Na2CuO2 + 2H2O
Al2(SO4)3 + 6NaOH = 2Al(OH)3  + 3Na2SO4
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
Al(OH)3 + NaOH = NaAlO2 + 2H2O

Answer 2

1) FeCl3 + NaOH → Fe(OH)3 ↓

The reaction between FeCl3 (iron(III) chloride) and NaOH (sodium hydroxide) results in the formation of Fe(OH)3 (iron(III) hydroxide) as a precipitate. The balanced equation for this reaction is:

FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl

2) Fe(OH)3 + H2SO4 → Fe2(SO4)3 + H2O

When Fe(OH)3 (iron(III) hydroxide) reacts with H2SO4 (sulfuric acid), it forms Fe2(SO4)3 (iron(III) sulfate) and water (H2O). The balanced equation for this reaction is:

2Fe(OH)3 + 3H2SO4 → Fe2(SO4)3 + 6H2O

3) Cu(OH)2 ↓ + NaOH → Cu(OH)2 + NaOH

The reaction between Cu(OH)2 (copper(II) hydroxide) and NaOH (sodium hydroxide) does not result in any significant change. It is a neutralization reaction where Cu(OH)2 remains unchanged. The balanced equation for this reaction is:

Cu(OH)2 + NaOH → Cu(OH)2 + NaOH

4) Al2(SO4)3 + NaOH → Al(OH)3 + Na2SO4

When Al2(SO4)3 (aluminum sulfate) reacts with NaOH (sodium hydroxide), it forms Al(OH)3 (aluminum hydroxide) and Na2SO4 (sodium sulfate). The balanced equation for this reaction is:

Al2(SO4)3 + 6NaOH → 2Al(OH)3 + 3Na2SO4

5) Al(OH)3 + H2SO4 → Al2(SO4)3 + 3H2O

When Al(OH)3 (aluminum hydroxide) reacts with H2SO4 (sulfuric acid), it forms Al2(SO4)3 (aluminum sulfate) and water (H2O). The balanced equation for this reaction is:

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

6) Al(OH)3 + NaOH → NaAlO2 + 2H2O

The reaction between Al(OH)3 (aluminum hydroxide) and NaOH (sodium hydroxide) results in the formation of NaAlO2 (sodium aluminate) and water (H2O). The balanced equation for this reaction is:

Al(OH)3 + NaOH → NaAlO2 + 2H2O

Please note that the reactions mentioned above are based on the information provided in the search result snippet from Source [[1]](https://portal.tpu.ru/SHARED/l/LYAMINA/uchebnaya_rabota/Tab/ChemistryP1_0.pdf).