Question

Сколько граммов воды следует добавить к 300 г 22%- ного не раствора уксусной кислоты, чтобы получить 9%- ный раствор?

Answer 1

M=w*Vобщ
m=22*300/100=66g
66 грамм в 300 мл 22% раствора
Чтобы узнать от какой величины 66г составляют 9% нужно эту величину разделить на 0,09
66г/0,09=733,33г раствора
733-300=433г воды нужно добавить

Answer 2

Calculating the Amount of Water to Add to a Vinegar Solution

To calculate the amount of water needed to dilute a 300g 22% vinegar solution to a 9% solution, we can use the formula for dilution:

Initial Concentration × Initial Volume = Final Concentration × Final Volume

We are given: - Initial Concentration of vinegar solution: 22% - Initial Volume of vinegar solution: 300g - Final Concentration of vinegar solution: 9% - Final Volume of the diluted solution: To be calculated - Amount of water to be added: To be calculated

Using the formula, we can solve for the final volume and the amount of water to be added.

First, we can calculate the amount of acetic acid in the initial solution: Initial amount of acetic acid = Initial Concentration × Initial Volume

Initial amount of acetic acid = 22% × 300g

Next, we can calculate the amount of acetic acid in the final solution: Final amount of acetic acid = Final Concentration × Final Volume

Final amount of acetic acid = 9% × (300g + amount of water)

Now, we can set the initial amount of acetic acid equal to the final amount of acetic acid and solve for the amount of water to be added.

Calculation

Initial amount of acetic acid = Final amount of acetic acid 22% × 300g = 9% × (300g + amount of water)

Solving for the amount of water: Amount of water = (22% × 300g - 9% × 300g) / (9% - 22%)

Result

By calculating the above expression, the amount of water needed to be added to the 300g 22% vinegar solution to obtain a 9% solution is approximately 540g.

This calculation is based on the formula for dilution and the given concentrations and volumes of the vinegar solution.