Вопрос задан 15.02.2019 в 15:26. Предмет Химия. Спрашивает Турлаков Роберт.

Найти объем газа выделившегося при воздействии 40.5 г алюминия с избытком соляной кислоты

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Отвечает Леонгардт Варя.
40.5г                              хл
2Al + 6HCl = 2AlCl3 + 3H2 
54                                 67,2

х=40,5*67,2/54=50,4л
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculating the Volume of Gas Produced from the Reaction of Aluminum with Excess Hydrochloric Acid

To calculate the volume of gas produced when 40.5 g of aluminum reacts with excess hydrochloric acid, we can use the ideal gas law equation, which is given by:

PV = nRT

Where: - P = pressure of the gas - V = volume of the gas - n = number of moles of the gas - R = ideal gas constant - T = temperature in Kelvin

First, we need to determine the number of moles of the gas produced by the reaction. The balanced chemical equation for the reaction between aluminum and hydrochloric acid is:

2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g)

From the balanced equation, we can see that 2 moles of aluminum produce 3 moles of hydrogen gas.

Given: - Mass of aluminum (Al) = 40.5 g - Molar mass of aluminum (Al) = 27 g/mol - Molar mass of hydrogen (H2) = 2 g/mol

Calculation Steps:

1. Calculate the number of moles of aluminum. 2. Use the mole ratio from the balanced chemical equation to find the number of moles of hydrogen gas produced. 3. Apply the ideal gas law to calculate the volume of hydrogen gas produced.

Step 1: Calculate the Number of Moles of Aluminum

The number of moles of aluminum can be calculated using the formula:

Number of moles = Mass / Molar mass

Substitute the given values: Number of moles of aluminum = 40.5 g / 27 g/mol

Step 2: Use the Mole Ratio to Find the Number of Moles of Hydrogen Gas

From the balanced chemical equation, 2 moles of aluminum produce 3 moles of hydrogen gas. Therefore, the number of moles of hydrogen gas produced can be calculated as follows:

Number of moles of hydrogen gas = (Number of moles of aluminum) * (3 moles of H2 / 2 moles of Al)

Step 3: Apply the Ideal Gas Law to Calculate the Volume of Hydrogen Gas

Using the ideal gas law equation, we can solve for the volume of hydrogen gas produced.

Given: - Pressure (P) is not provided in the search results. - Temperature (T) is not provided in the search results. - The ideal gas constant (R) is 0.0821 L·atm/(K·mol).

We are unable to proceed with the calculation as the pressure and temperature values are not provided in the search results. These values are essential for calculating the volume of gas using the ideal gas law equation.

If you have the pressure and temperature values, please provide them, and I can assist you further with the calculation.

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