Question

1 задание: H4C+O2--->??? 2 задание: определить массовую долю водорода в метане (метан- H4C) ПРОШУ,РЕШИТЕ КАК МОЖНО БЫСТРЕЕ!!!!!!!!!!!!!!!!!!!!

Answer 1

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Answer 2

1 задание: H4C O2 -> ???

To determine the products of the reaction between H4C and O2, we need to balance the equation first. However, it seems that there is a typo in the equation you provided. The correct formula for methane is CH4, not H4C. Therefore, the balanced equation for the reaction between CH4 and O2 is:

CH4 + 2O2 -> CO2 + 2H2O In this reaction, methane (CH4) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).

2 задание: Определить массовую долю водорода в метане (метан - CH4)

To determine the mass fraction of hydrogen in methane (CH4), we need to calculate the ratio of the molar mass of hydrogen to the molar mass of methane.

The molar mass of hydrogen (H2) is approximately 2 g/mol, and the molar mass of methane (CH4) is approximately 16 g/mol. Since methane contains 4 hydrogen atoms, the mass of hydrogen in methane is 4 * 2 g/mol = 8 g/mol.

To calculate the mass fraction of hydrogen in methane, we divide the mass of hydrogen by the molar mass of methane and multiply by 100:

Mass fraction of hydrogen in methane = (8 g/mol / 16 g/mol) * 100% = 50%

Therefore, the mass fraction of hydrogen in methane is 50%.

Please note that the molar mass values used here are approximate and may vary slightly depending on the source.