Question

Закончи соответствующие ураанения реакций и расставь коэффинценты. Помогите пожалуйста 1) SO2 + H2O = SO3 +H20 = P4 010 + H2O = 2) N2O5 + H2O = CO2 + H2O = SeO3 + H2O =

Answer 1

1) SO2+H2O=H2SO3

SO3+H2O=H2SO4

P4O10+H2O=4H3PO4

2) N2O5+H2O=2HNO3

CO2+H2O=H2CO3

SeO3+H2O=H2SeO4

Answer 2

1) SO2+H2O=H2SO3 сернистая к-та
SO3+H2O=H2SO4 серная к-та
P4O10+6H2O=4H3PO4 фосфорная к-та
2)N2O5+H2O=2HNO3 азотная к-та
CO2+H2O=H2CO3 угольная к-та
SeO3+H2O=H2SeO4 селеновая к-та

Answer 3

Balancing Chemical Equations

1) SO2 + H2O = SO3 + H2O

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by balancing the sulfur (S) atoms. There is 1 sulfur atom on the left side and 1 sulfur atom on the right side, so sulfur is already balanced.

Next, let's balance the oxygen (O) atoms. There are 2 oxygen atoms in SO2 and 3 oxygen atoms in SO3, so we need to add an extra oxygen atom on the left side. We can do this by adding a coefficient of 2 in front of H2O on the left side:

SO2 + 2H2O = SO3 + H2O

Now, let's balance the hydrogen (H) atoms. There are 4 hydrogen atoms in 2H2O on the left side and 2 hydrogen atoms in H2O on the right side. We can balance the hydrogen atoms by adding a coefficient of 2 in front of H2O on the right side:

SO2 + 2H2O = SO3 + 2H2O

The equation is now balanced.

2) N2O5 + H2O = CO2 + H2O

To balance this equation, let's start by balancing the nitrogen (N) atoms. There are 2 nitrogen atoms in N2O5 and 1 nitrogen atom in CO2, so we need to add an extra nitrogen atom on the right side. We can do this by adding a coefficient of 2 in front of NO2 on the right side:

N2O5 + H2O = 2CO2 + H2O

Next, let's balance the oxygen (O) atoms. There are 5 oxygen atoms in N2O5 and 4 oxygen atoms in 2CO2, so we need to add an extra oxygen atom on the left side. We can do this by adding a coefficient of 2 in front of H2O on the left side:

N2O5 + 2H2O = 2CO2 + H2O

Finally, let's balance the hydrogen (H) atoms. There are 4 hydrogen atoms in 2H2O on the left side and 2 hydrogen atoms in H2O on the right side. We can balance the hydrogen atoms by adding a coefficient of 2 in front of H2O on the right side:

N2O5 + 2H2O = 2CO2 + 2H2O

The equation is now balanced.

3) SeO3 + H2O = ??

To balance this equation, we need more information about the products. Could you please provide the missing product(s) for this reaction?