Question

Для получения этилового спирта уксусной кислоты были взяты 100г уксусной кислоты и 69г этилового спирта. чему равна масса образующего эфира?

Answer 1

Рассчитаем  вещество в избытке
vCH3COOH=100/60=1.6mol - isbytok
vC2H5OH=69/46=1.5mol
                      69g               xg
CH3COOH+C2H5OH=CH3COOC2H2H5+H2O
                      46g                88g
x=69·88/46=132g

Answer 2

Надо правильно писать задачу , надо получить этиловый эфир уксусной кислоты???
СН3-СООН+С2Н5ОН=Сн3-СОО-С2Н5 +Н2О
nCH3COOH=100/Mr=100/60=1,67 моль
nC2H5OH=69/Mr=69/46=1,5моль
Решаем по недостатку
1,5<1,67
nCH3COOC2H5=1,5
mCH3COOC2H5=1,5*Mr=1,5*88=132г масса эфира

Answer 3

Calculating the Mass of the Formed Ester

To calculate the mass of the formed ester, we can use the formula:

M(R'OH) = m(R'OH) / n(R'OH)

Where: - M(R'OH) is the molar mass of the alcohol (in this case, the ethyl alcohol). - m(R'OH) is the mass of the alcohol used (in this case, 69g). - n(R'OH) is the number of moles of the alcohol.

Using the given information, we can calculate the mass of the formed ester.

Calculation

Using the provided data: - Mass of acetic acid (CH3COOH) = 100g - Mass of ethyl alcohol (C2H5OH) = 69g

We can calculate the molar mass of the alcohol (ethyl alcohol) using the formula: M(R'OH) = m(R'OH) / n(R'OH)

From the search results, the molar mass of ethyl alcohol (C2H5OH) is approximately 46.

Therefore, the mass of the formed ester can be calculated using the molar ratio of the reactants and the molar mass of the alcohol.

Conclusion

The mass of the formed ester can be calculated using the molar mass of the alcohol and the given masses of acetic acid and ethyl alcohol.