Question

Определите степень окисления элементов в соединениях :P2O5 ;K2S ;CU

Answer 1

Р2О5 = О со степенью окисления "-2", Р со степенью окисления "+5"
К2S = S со степенью окисления "-2", К со степенью окисления "+1"

Answer 2

Determining Oxidation States of Elements in Compounds

In the compounds provided, the oxidation states of the elements are as follows:

1. P2O5: - The oxidation state of oxygen is typically -2 in compounds, so the total oxidation state for the compound is 0. - To calculate the oxidation state of phosphorus in P2O5, we can use the formula: 2x + 5(-2) = 0, where x is the oxidation state of phosphorus. - Solving for x, we get: 2x - 10 = 0, 2x = 10, x = +5. - Therefore, the oxidation state of phosphorus in P2O5 is +5.

2. K2S: - The oxidation state of potassium (K) in compounds is typically +1, and the oxidation state of sulfur (S) is typically -2. - Using the formula 2x + (-2) = 0, where x is the oxidation state of sulfur, we find: 2x - 2 = 0, 2x = 2, x = +1. - Therefore, the oxidation state of sulfur in K2S is -2.

3. Cu: - The oxidation state of copper (Cu) can vary in different compounds. - In its elemental form, copper has an oxidation state of 0. - In many compounds, copper has an oxidation state of +2, such as in CuO or CuCl2. - However, copper can also have an oxidation state of +1, such as in Cu2O. - Therefore, the oxidation state of copper in the compound "Cu" can be either +1 or +2.

These are the oxidation states of the elements in the given compounds. If you have further questions or need more information, feel free to ask!