Question

1. Вещества, молекулы которых образованы только ковалентной неполярной связью, - это 1) хлор и хлороводород2) водород и азот3) водород и сероводород4) хлороводород и сероводород2. Выяислите массу и объем ( н. у. ) кислорода, который можно получить из 850г. 3%-ого раствора пероксида водорода?

Answer 1

1. Ответ 2
2. H2O2=>O2+H2
D(H2O2)=850•0.03:34=0.75 моль
V(O2)=0.75•22.4=16.8 литров

Answer 2

1.ответ 2

2.H2O2=>O2+H2

D(H2O2)=850*0.03/34=0.75 моль

V(O2)=0.75*22.4=16.8 литров 

Answer 3

Substances with only covalent nonpolar bonds

The substances whose molecules are formed only by covalent nonpolar bonds are: 1) Chlorine (Cl2) and hydrogen chloride (HCl) [[1]]. 2) Hydrogen (H2) and nitrogen (N2) [[2]]. 3) Hydrogen (H2) and hydrogen sulfide (H2S) [[3]]. 4) Hydrogen chloride (HCl) and hydrogen sulfide (H2S) [[4]].

Calculating the mass and volume of oxygen from hydrogen peroxide

To calculate the mass and volume of oxygen that can be obtained from 850g of a 3% solution of hydrogen peroxide, we need to consider the chemical equation for the decomposition of hydrogen peroxide (H2O2) into water (H2O) and oxygen (O2):

2H2O2 -> 2H2O + O2

From the equation, we can see that for every 2 moles of hydrogen peroxide, 1 mole of oxygen is produced. To determine the number of moles of hydrogen peroxide in the solution, we need to use its molar mass.

The molar mass of hydrogen peroxide (H2O2) is: 2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol

To calculate the number of moles of hydrogen peroxide in 850g of a 3% solution, we can use the following formula:

moles = mass / molar mass

moles = 850g / 34.02 g/mol = 24.97 mol

Since the molar ratio between hydrogen peroxide and oxygen is 2:1, we can calculate the number of moles of oxygen produced:

moles of oxygen = moles of hydrogen peroxide / 2 = 24.97 mol / 2 = 12.49 mol

To calculate the mass of oxygen produced, we can use its molar mass:

molar mass of oxygen (O2) = 2(16.00 g/mol) = 32.00 g/mol

mass of oxygen = moles of oxygen * molar mass of oxygen mass of oxygen = 12.49 mol * 32.00 g/mol = 399.68 g

Therefore, the mass of oxygen that can be obtained from 850g of a 3% solution of hydrogen peroxide is approximately 399.68 grams.

To calculate the volume of oxygen produced, we need to use the ideal gas law equation:

PV = nRT

Where: P = pressure (atm) V = volume (L) n = number of moles R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature (K)

At standard temperature and pressure (STP), the pressure is 1 atm and the temperature is 273 K. Therefore, we can calculate the volume of oxygen using the following formula:

V = nRT / P V = 12.49 mol * 0.0821 L·atm/(mol·K) * 273 K / 1 atm V = 273.02 L

Therefore, the volume of oxygen that can be obtained from 850g of a 3% solution of hydrogen peroxide at STP is approximately 273.02 liters.

Note: The above calculations assume ideal conditions and may not account for real-world factors such as incomplete reactions or impurities in the hydrogen peroxide solution.