Question

(Даю 30 баллов) Материальная точка движется равноускоренно из состояние покоя и 1/9 часть пути проходит за 1 с. За какое время ( с ) она проходит остальную часть пути. (С пояснением пожалуйста)

Answer 1

1,9=1 сек.
9-1 =8 сек.

Answer 2

Тут чистая логика. Он проходит за 1 с 1/9 часть дороги. То есть дорога поделена на 9 частей, и материальная точка прошла только 1 часть и 9. Осталось 8. На каждую часть уходит 1 с( т.к движение равноускоренное). И на остальные 8 частей он потратит соответственно 8 с

Answer 3

Problem Analysis

We are given that a material point is moving with constant acceleration from a state of rest. We also know that it covers 1/9th of the total distance in 1 second. We need to find the time it takes to cover the remaining distance.

Solution

Let's assume the total distance covered by the material point is d units. We are given that the material point covers 1/9th of the total distance in 1 second. Therefore, the distance covered in 1 second is d/9 units.

Since the material point is moving with constant acceleration, we can use the equations of motion to solve this problem. The equation that relates distance, initial velocity, time, and acceleration is:

d = ut + (1/2)at^2

Where: - d is the distance covered - u is the initial velocity (which is 0 in this case since the material point starts from rest) - t is the time taken - a is the acceleration

We are given that the material point is moving with constant acceleration, so we can assume that the acceleration is the same throughout the motion.

Let's substitute the given values into the equation and solve for time:

d = 0*t + (1/2)a*t^2

Since the material point starts from rest, the initial velocity u is 0. Therefore, the equation simplifies to:

d = (1/2)a*t^2

Now, we can solve for time t:

t^2 = (2d)/a

Taking the square root of both sides:

t = sqrt((2d)/a)

To find the time it takes to cover the remaining distance, we need to subtract the time it takes to cover 1/9th of the total distance from the total time. Let's calculate that:

Total time = t + 1

Remaining time = Total time - 1

Now, let's substitute the values and solve for the remaining time:

Remaining time = (sqrt((2d)/a)) + 1 - 1

Simplifying:

Remaining time = sqrt((2d)/a)

Therefore, the material point takes sqrt((2d)/a) seconds to cover the remaining distance.

Answer

The material point takes sqrt((2d)/a) seconds to cover the remaining distance, where d is the total distance covered and a is the constant acceleration.