Question

1)Рассчитайте массу( в граммах) уксусной кислоты, необходимой для нейтрализации гидроксида калия химическим количеством 0,4 моль2) Рассчитайте химическое количество( моль) уксусной кислоты, которую можно нейтролизовать раствором щелочи массой 40 гр с массовой долей гидроскида натрия 25 %

Answer 1

№1

    х моль     0,4 моль

СН3СООН + КОН = СН3СООК + Н2О

1 моль        1 моль

х = 0,4

1     1

х = 0,4

n(CH3COOH) = 0,4 моль

m = n*M

M(CH3COOH) = 12 + 1*3 + 12 + 16 + 16 + 1 = 60 г/моль

m(CH3COOH) = 0,4 моль * 60 г/моль = 24 г

Ответ: 24 г

 

№2

x моль         0,25 моль

CH3COOH + NaOH = CH3COONa + H2O

1 моль         1 моль

m вещ-ва = m р-ра * w

m вещ-ва (NaOH) = 40 г * 0,25 = 10 г

n = m/M

M(NaOH) = 23 + 16 + 1= 40 г/моль

n(NaOH) = 10 г/ 40 г/моль = 0,25 моль

х = 0,25

1      1

х = 0,25

n(CH3COOH) = 0,25 моль

Ответ: 0,25 моль

Answer 2

Calculation of the mass of acetic acid needed to neutralize potassium hydroxide:

To calculate the mass of acetic acid needed to neutralize potassium hydroxide, we need to use the balanced chemical equation for the reaction between acetic acid (CH3COOH) and potassium hydroxide (KOH):

CH3COOH + KOH -> CH3COOK + H2O

From the balanced equation, we can see that the stoichiometric ratio between acetic acid and potassium hydroxide is 1:1. This means that 1 mole of acetic acid reacts with 1 mole of potassium hydroxide.

Given that the chemical quantity of potassium hydroxide is 0.4 moles, we can conclude that the required amount of acetic acid is also 0.4 moles.

To calculate the mass of acetic acid, we need to know its molar mass. The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol.

Using the formula:

Mass = Molar mass x Moles

we can calculate the mass of acetic acid:

Mass = 60.05 g/mol x 0.4 mol = 24.02 grams

Therefore, the mass of acetic acid needed to neutralize potassium hydroxide is approximately 24.02 grams.