Question

Расставьте коэффициенты в схемах химических реакцийа)Ag2O-->Ag+O2↑б)Zn+ CI2 -->AlСI3в)Na+ H2O--> NaOH+ H2↑помогите пожалуйста!

Answer 1

А) 2Ag2O--->4Ag+O2↑
б)Zn+ CI2 -->AlСI3 (?)

Answer 2

Chemical Equations and Balancing Coefficients

Chemical equations represent the reactants and products involved in a chemical reaction. Balancing coefficients are used to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each of the given chemical equations and balance the coefficients.

a) Ag2O -> Ag + O2↑

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides. Let's start with silver (Ag). There are two silver atoms on the left side and one on the right side. To balance the silver atoms, we can put a coefficient of 2 in front of Ag on the right side:

Ag2O -> 2Ag + O2↑

Now let's balance the oxygen (O) atoms. There are two oxygen atoms on the left side and two on the right side. The equation is now balanced:

Ag2O -> 2Ag + O2↑

b) ZnCl2 -> AlCl3

In this equation, we have zinc chloride (ZnCl2) on the left side and aluminum chloride (AlCl3) on the right side. To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides.

Let's start with zinc (Zn). There is one zinc atom on the left side and none on the right side. To balance the zinc atoms, we can put a coefficient of 2 in front of ZnCl2 on the left side:

2ZnCl2 -> AlCl3

Now let's balance the chlorine (Cl) atoms. There are two chlorine atoms on the left side and three on the right side. To balance the chlorine atoms, we can put a coefficient of 3 in front of AlCl3 on the right side:

2ZnCl2 -> 3AlCl3

The equation is now balanced.

c) Na + H2O -> NaOH + H2↑

In this equation, we have sodium (Na) and water (H2O) on the left side, and sodium hydroxide (NaOH) and hydrogen gas (H2) on the right side. Let's balance the equation.

Starting with sodium (Na), there is one sodium atom on the left side and one on the right side. The sodium atoms are already balanced.

Next, let's balance the oxygen (O) atoms. There are two oxygen atoms in water (H2O) on the left side and one oxygen atom in sodium hydroxide (NaOH) on the right side. To balance the oxygen atoms, we can put a coefficient of 2 in front of NaOH on the right side:

Na + H2O -> NaOH + H2↑

Finally, let's balance the hydrogen (H) atoms. There are two hydrogen atoms in water (H2O) on the left side and two hydrogen atoms in hydrogen gas (H2) on the right side. The equation is now balanced:

Na + 2H2O -> NaOH + H2↑

I hope this helps! Let me know if you have any further questions.