Question

Составте уравнения реакций горения ПетинаС2H12 2) Закончите уравнение реакций которые могут быть практически осуществимы a)Mg+H2S04- (Это ---> стрелочка) б) SO2+H2O---> в Ag+HCL---> г) HCL+H2O д) Rb2+O+H2O---> e) Mg+H2O 4. Смешали 200г раствора с массовой долей кислоты 5% и 300 Г раствора с массовой долей кислоты 10%. Вычислите массовую долю (в%) кислоты в полученном растворе. (БЛАГОДАРЮ ВАС ЗАРАНИЕ СПАСИБО МОЙ СПАСИТЕЛЬ) Кто бы ты не был У тебя всё получится! хелп плыыз)

Answer 1

С5H12+13O2-->5CO2+6H2O

2) a , б , е
4)
масса 1 раствора = 200г
массовая доля 1 вещества =5%
масса1 вещества = 200*5%/100%=10 г
масса 2 раствора = 300 г
массовая доля 2 вещества =10%
масса 2 вещества = 300*10%/100%=30 г
масса общая раствора = 200 + 300 = 500 г
масса общая вещества = 10+30 = 40 г
массовая доля общая = 40/500*100%=8%
ответ 8%

Answer 2

Equations of Combustion Reactions:

The combustion reaction of pentane (C5H12) can be represented by the following equation:

C5H12 + 8O2 → 5CO2 + 6H2O [[1]]

Completion of Reactions:

a) The reaction between magnesium (Mg) and sulfuric acid (H2SO4) can be represented as follows:

Mg + H2SO4 → MgSO4 + H2 [[2]]

b) The reaction between sulfur dioxide (SO2) and water (H2O) does not yield a practical reaction.

c) The reaction between silver (Ag) and hydrochloric acid (HCl) can be represented as follows:

Ag + HCl → AgCl + H2 [[3]]

d) The reaction between hydrochloric acid (HCl) and water (H2O) does not yield a practical reaction.

e) The reaction between rubidium oxide (Rb2O) and water (H2O) can be represented as follows:

Rb2O + H2O → 2RbOH [[4]]

Calculation of Acid Concentration:

To calculate the mass percentage of acid in the resulting solution, we need to consider the mass of the acid in each solution and the total mass of the resulting solution.

Let's assume the resulting solution has a total mass of 500 g.

The first solution has a mass of 200 g and a mass percentage of acid of 5%. Therefore, it contains 0.05 * 200 g = 10 g of acid.

The second solution has a mass of 300 g and a mass percentage of acid of 10%. Therefore, it contains 0.10 * 300 g = 30 g of acid.

The total mass of acid in the resulting solution is 10 g + 30 g = 40 g.

The mass percentage of acid in the resulting solution is (40 g / 500 g) * 100% = 8%.

Therefore, the resulting solution has a mass percentage of acid of 8%.

I hope this helps! Let me know if you have any further questions.