Question

ПОМОГИТЕ! Уравнять электронно-ионным методом,указать окислитель и восстановитель.1) K2MnO4+KJ+H2SO4>MnSO4+J2+K2SO4+H2O2) Mg + H2SO4 = MgSO4 + S + H2O

Answer 1

Решение на фото.................................

Answer 2

Balancing the Equation: K2MnO4 + KI + H2SO4 -> MnSO4 + I2 + K2SO4 + H2O

To balance the equation using the electron-ion method, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by balancing the atoms that appear in multiple compounds:

1. Balancing the potassium (K) atoms: - There are 2 K atoms on the left side (in K2MnO4 and K2SO4). - To balance the K atoms, we need to put a coefficient of 2 in front of KI and K2SO4.

The equation becomes: 2K2MnO4 + 2KI + H2SO4 -> MnSO4 + I2 + 2K2SO4 + H2O

2. Balancing the sulfur (S) atoms: - There is 1 S atom on the left side (in H2SO4). - To balance the S atoms, we need to put a coefficient of 2 in front of H2SO4.

The equation becomes: 2K2MnO4 + 2KI + 2H2SO4 -> MnSO4 + I2 + 2K2SO4 + H2O

3. Balancing the oxygen (O) atoms: - There are 8 O atoms on the left side (in K2MnO4 and H2SO4). - To balance the O atoms, we need to put a coefficient of 4 in front of K2MnO4.

The equation becomes: 4K2MnO4 + 2KI + 2H2SO4 -> MnSO4 + I2 + 2K2SO4 + H2O

4. Balancing the manganese (Mn) atoms: - There are 4 Mn atoms on the left side (in K2MnO4). - To balance the Mn atoms, we need to put a coefficient of 4 in front of MnSO4.

The final balanced equation is: 4K2MnO4 + 2KI + 2H2SO4 -> 4MnSO4 + I2 + 2K2SO4 + H2O

In this equation, K2MnO4 is the oxidizing agent (or the oxidant) because it causes the iodide ion (I-) to be oxidized to iodine (I2). The KI is the reducing agent (or the reductant) because it is being oxidized, losing electrons to form iodine.

Balancing the Equation: Mg + H2SO4 -> MgSO4 + S + H2O

To balance the equation using the electron-ion method, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by balancing the atoms that appear in multiple compounds:

1. Balancing the magnesium (Mg) atoms: - There is 1 Mg atom on the left side. - To balance the Mg atoms, we need to put a coefficient of 1 in front of MgSO4.

The equation becomes: Mg + H2SO4 -> MgSO4 + S + H2O

2. Balancing the sulfur (S) atoms: - There is 1 S atom on the right side. - To balance the S atoms, we need to put a coefficient of 1 in front of S.

The equation becomes: Mg + H2SO4 -> MgSO4 + S + H2O

3. Balancing the hydrogen (H) atoms: - There are 4 H atoms on the right side (in H2SO4 and H2O). - To balance the H atoms, we need to put a coefficient of 4 in front of H2O.

The equation becomes: Mg + H2SO4 -> MgSO4 + S + 4H2O

The final balanced equation is: Mg + H2SO4 -> MgSO4 + S + 4H2O

In this equation, Mg is the reducing agent (or the reductant) because it is being oxidized, losing electrons to form magnesium sulfate (MgSO4). The H2SO4 is the oxidizing agent (or the oxidant) because it causes the magnesium to be oxidized.