Question

Решите задачи пожалуйста. СРОЧНО Какой объем водорода образуется при взаимодействии с 6,5г Zn содержащего 10 % примесей с Hcl. Какой объем водорода образуется при взаимодействии с 5.11г Mg содержащего 10% примесей с Hcl ЗАРАНЕЕ СПАСИБО

Answer 1

1. W(Zn) = 100 - W(примесей) = 100 - 10 = 90% = 0,9
m(Zn чист.) = m(Zn с примесями)xW(Zn) = 6,5x0,9 = 5,85 г
Zn + 2HCl = ZnCl2 + H2
n(H2) = n(Zn) = m(Zn)/M(Zn) = 5,85/65 = 0,09 моль
V(H2) = n(H2)xVm = 0,09x22,4 = 2,016 л

2. W(Mg) = 100 - W(примесей) = 100 - 10 = 90% = 0,9
m(Mg чист.) = m(Mg с примесями)xW(Mg) = 5,11x0,9 = 4,599 г
Mg + 2HCl = MgCl2 + H2
n(H2) = n(Mg) = m(Mg)/M(Mg) = 4,599/24 = 0,19 моль
V(H2) = nxVm = 0,19x22,4 = 4,256 л

Answer 2

To calculate the volume of hydrogen gas produced in the reaction between a given mass of a metal and hydrochloric acid (HCl), we need to use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in chemical reactions.

Reaction Equation:

The reaction between a metal (Zn or Mg) and HCl can be represented by the following balanced chemical equation:

Zn + 2HCl → ZnCl2 + H2

Mg + 2HCl → MgCl2 + H2

Given Information:

1. For the reaction between 6.5g of Zn and HCl containing 10% impurities: - Mass of Zn: 6.5g - Impurities in HCl: 10%

2. For the reaction between 5.11g of Mg and HCl containing 10% impurities: - Mass of Mg: 5.11g - Impurities in HCl: 10%

Calculation Steps:

1. Calculate the mass of pure Zn or Mg in the given samples by subtracting the impurities: - Mass of pure Zn = Mass of Zn - (Impurities in HCl) - Mass of pure Mg = Mass of Mg - (Impurities in HCl)

2. Convert the mass of pure Zn or Mg to moles using their respective molar masses: - Molar mass of Zn = 65.38 g/mol - Molar mass of Mg = 24.31 g/mol - Moles of pure Zn = Mass of pure Zn / Molar mass of Zn - Moles of pure Mg = Mass of pure Mg / Molar mass of Mg

3. Use the stoichiometry of the balanced chemical equation to determine the moles of hydrogen gas produced: - According to the balanced equation, 1 mole of Zn or Mg produces 1 mole of H2 gas.

4. Convert the moles of hydrogen gas to volume using the ideal gas law: - The ideal gas law equation is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. - Assuming the reaction takes place at standard temperature and pressure (STP), we can use the following values: - Pressure (P) = 1 atm - Temperature (T) = 273.15 K - Ideal gas constant (R) = 0.0821 L·atm/(mol·K)

- Rearrange the ideal gas law equation to solve for volume (V): V = (n * R * T) / P

Calculation for the first reaction (Zn + HCl):

1. Calculate the mass of pure Zn: - Impurities in HCl = 10% of HCl mass = 0.1 * Mass of HCl - Mass of HCl = Mass of Zn + Impurities in HCl = 6.5g + 0.1 * 6.5g - Mass of pure Zn = Mass of Zn - (Impurities in HCl) = 6.5g - 0.1 * 6.5g

2. Convert the mass of pure Zn to moles: - Moles of pure Zn = Mass of pure Zn / Molar mass of Zn

3. Determine the moles of hydrogen gas produced: - According to the balanced equation, 1 mole of Zn produces 1 mole of H2 gas.

4. Convert the moles of hydrogen gas to volume at STP: - V = (n * R * T) / P

Calculation for the second reaction (Mg + HCl):

1. Calculate the mass of pure Mg: - Impurities in HCl = 10% of HCl mass = 0.1 * Mass of HCl - Mass of HCl = Mass of Mg + Impurities in HCl = 5.11g + 0.1 * 5.11g - Mass of pure Mg = Mass of Mg - (Impurities in HCl) = 5.11g - 0.1 * 5.11g

2. Convert the mass of pure Mg to moles: - Moles of pure Mg = Mass of pure Mg / Molar mass of Mg

3. Determine the moles of hydrogen gas produced: - According to the balanced equation, 1 mole of Mg produces 1 mole of H2 gas.

4. Convert the moles of hydrogen gas to volume at STP: - V = (n * R * T) / P

Please provide the molar mass of HCl and the temperature and pressure conditions if they are different from the standard values.