Question

S--BaS--H2S--SO2--K2SO3--SO2--SO3--H2SO4.

Answer 1

ٍS + Ba = BaS
BaS + H2 = Ba + H2S
H2S + O2 = SO2 + H2
SO2 + 2 KOH = K2SO3 + H2
K2SO3 ------> 2 KOH + SO2
2 SO2 + O2 = 2 SO3
SO3 + H2O = H2SO4

Answer 2

Chemical Reactions:

The given sequence of chemical reactions is as follows: S -- BaS -- H2S -- SO2 -- K2SO3 -- SO2 -- SO3 -- H2SO4.

1. S --> BaS: The reaction between sulfur (S) and barium (Ba) forms barium sulfide (BaS). 2. BaS --> H2S: Barium sulfide (BaS) reacts with hydrochloric acid (HCl) to produce hydrogen sulfide (H2S) and barium chloride (BaCl2) [[2]](https://publications.hse.ru/pubs/share/direct/249069387.pdf). 3. H2S --> SO2: Hydrogen sulfide (H2S) can be oxidized to sulfur dioxide (SO2) under certain conditions. 4. SO2 --> K2SO3: Sulfur dioxide (SO2) can react with potassium hydroxide (KOH) to form potassium sulfite (K2SO3). 5. K2SO3 --> SO2: Potassium sulfite (K2SO3) can be decomposed to sulfur dioxide (SO2) under certain conditions. 6. SO2 --> SO3: Sulfur dioxide (SO2) can be further oxidized to sulfur trioxide (SO3) under certain conditions. 7. SO3 --> H2SO4: Sulfur trioxide (SO3) reacts with water (H2O) to form sulfuric acid (H2SO4).

Summary:

The given sequence of reactions involves the transformation of sulfur (S) into various sulfur compounds, including barium sulfide (BaS), hydrogen sulfide (H2S), sulfur dioxide (SO2), potassium sulfite (K2SO3), sulfur trioxide (SO3), and sulfuric acid (H2SO4). These reactions demonstrate the oxidation and reduction processes of sulfur, as well as the formation of different sulfur compounds through chemical reactions.

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