Question

Найти массу,обьём для 2-х молей MgSiO3,Найти массовые доли в элементах молекул.Помогите пожалуйста!Прошу.

Answer 1

N=2 (моль)

M(MgSiO3)=24+28+3*16=100 (г/моль)
m=n*M=2*100=200 (г)
V=Vm*n, где Vm - объем газа при н.у. = 22.4 (л/моль)
V=22.4*2=44.8 (л)

M(MgSiO3)=24+28+3*16=100 (г/моль)
W(Mg)=24/100=0.24=24%
W(Si)=28/100=0.28=28%
W(O)=48/100=0.48=48%

Answer 2

Finding the Mass and Volume for 2 Moles of MgSiO3

To find the mass and volume for 2 moles of MgSiO3, we need to know the molar mass of MgSiO3 and the molar volume of a gas at standard temperature and pressure (STP).

The molar mass of MgSiO3 can be calculated by adding up the atomic masses of magnesium (Mg), silicon (Si), and oxygen (O) in the compound. According to the periodic table, the atomic masses are approximately:

- Mg: 24.31 g/mol - Si: 28.09 g/mol - O: 16.00 g/mol

So, the molar mass of MgSiO3 is:

Mg: 24.31 g/mol Si: 28.09 g/mol O: 16.00 g/mol

Adding these up, we get:

Molar mass of MgSiO3 = 24.31 g/mol + 28.09 g/mol + (3 * 16.00 g/mol) = 100.39 g/mol

Therefore, the molar mass of MgSiO3 is approximately 100.39 g/mol.

To find the mass for 2 moles of MgSiO3, we can use the following equation:

Mass = Molar mass * Number of moles

Substituting the values, we have:

Mass = 100.39 g/mol * 2 mol = 200.78 g

Therefore, the mass of 2 moles of MgSiO3 is approximately 200.78 grams.

Unfortunately, the search results did not provide information about the molar volume of MgSiO3 at STP. If you need information about the volume of 2 moles of MgSiO3, please let me know and I will try to find the information for you.

Mass Percentages of Elements in the Molecule

To find the mass percentages of the elements in the MgSiO3 molecule, we need to calculate the mass of each element and then divide it by the total molar mass of MgSiO3.

The molar mass of MgSiO3 is 100.39 g/mol, as calculated earlier.

To find the mass of each element, we can use the atomic masses from the periodic table:

- Mg: 24.31 g/mol - Si: 28.09 g/mol - O: 16.00 g/mol

The molecular formula of MgSiO3 indicates that there is 1 magnesium atom (Mg), 1 silicon atom (Si), and 3 oxygen atoms (O) in each molecule of MgSiO3.

Therefore, the mass of each element in one molecule of MgSiO3 is:

- Mass of Mg = 24.31 g/mol - Mass of Si = 28.09 g/mol - Mass of O = 3 * 16.00 g/mol = 48.00 g/mol

To calculate the mass percentages, we divide the mass of each element by the total molar mass of MgSiO3 and multiply by 100:

- Mass percentage of Mg = (24.31 g/mol / 100.39 g/mol) * 100% ≈ 24.23% - Mass percentage of Si = (28.09 g/mol / 100.39 g/mol) * 100% ≈ 27.95% - Mass percentage of O = (48.00 g/mol / 100.39 g/mol) * 100% ≈ 47.82%

Therefore, the mass percentages of magnesium, silicon, and oxygen in the MgSiO3 molecule are approximately 24.23%, 27.95%, and 47.82%, respectively.

I hope this helps! Let me know if you have any further questions.