Question

Сколько моль содержится в 0,25 л кислорода при н.у.?

Answer 1

n(количество вещества)=V/V=0,250/22,4=0,01моль

Answer 2

Calculation of Moles of Oxygen

To calculate the number of moles of oxygen in 0.25 L at standard temperature and pressure (n.u.), we need to use the ideal gas law equation:

PV = nRT

Where: - P is the pressure (atmospheres) - V is the volume (liters) - n is the number of moles - R is the ideal gas constant (0.0821 L·atm/(mol·K)) - T is the temperature (Kelvin)

At standard temperature and pressure (n.u.), the pressure is 1 atmosphere and the temperature is 273.15 Kelvin.

Let's substitute the given values into the equation:

1 atm * 0.25 L = n * 0.0821 L·atm/(mol·K) * 273.15 K

Simplifying the equation:

0.25 = n * 22.414

Solving for n:

n = 0.25 / 22.414

Calculating the value:

n ≈ 0.0112 moles

Therefore, there are approximately 0.0112 moles of oxygen in 0.25 L at standard temperature and pressure (n.u.).

Please note that the calculation assumes ideal gas behavior and standard temperature and pressure conditions.