Question

Сколько грамм углекислого газа выделится при сжигании 570 грамм 96%-ного раствора метанола. Срочно помогите пожалуйста, буду благодарен:)

Answer 1

2CH3OH + 3O2 = 2CO2 + 4H2O
m(CH3OH) = (570*96)/100 = 547,2 г
n(CH3OH) = m(CH3OH) / M(CH3OH) = 547,2 / 32 = 17,1 моль
n(CO2) = n(CH3OH) (по реакции)
m(CO2) = n(CO2) * M(CO2) = 17,1 * 44 = 752,4 г
Ответ: 752,4 грамма CO2

Answer 2

Calculation of Carbon Dioxide Produced from Burning Methanol Solution

To calculate the amount of carbon dioxide (CO2) produced from burning a 570-gram sample of a 96%-concentration methanol solution, we need to consider the chemical equation for the combustion of methanol:

2CH3OH + 3O2 → 2CO2 + 4H2O

From this equation, we can see that for every 2 moles of methanol (CH3OH) burned, 2 moles of carbon dioxide (CO2) are produced.

To determine the number of moles of methanol in the given sample, we can use the formula:

moles = mass / molar mass

The molar mass of methanol (CH3OH) is approximately 32.04 g/mol.

Using this information, we can calculate the number of moles of methanol in the 570-gram sample:

moles of methanol = 570 g / 32.04 g/mol

Now, since the methanol solution is 96% concentrated, we need to multiply the number of moles of methanol by 0.96 to account for the concentration:

moles of methanol in the solution = (570 g / 32.04 g/mol) * 0.96

Next, we can use the stoichiometry of the balanced equation to determine the number of moles of carbon dioxide produced:

moles of CO2 = (moles of methanol in the solution) * (2 moles of CO2 / 2 moles of CH3OH)

Finally, we can convert the moles of carbon dioxide to grams using the molar mass of carbon dioxide (44.01 g/mol):

grams of CO2 = (moles of CO2) * (44.01 g/mol)

Let's calculate the result:

moles of methanol = 570 g / 32.04 g/mol = 17.8 mol moles of methanol in the solution = 17.8 mol * 0.96 = 17.088 mol moles of CO2 = 17.088 mol * (2 mol CO2 / 2 mol CH3OH) = 17.088 mol grams of CO2 = 17.088 mol * 44.01 g/mol = 751.9 g

Therefore, approximately 751.9 grams of carbon dioxide will be produced when burning a 570-gram sample of a 96%-concentration methanol solution.

Please note that the above calculation assumes complete combustion of methanol and does not take into account any other byproducts or impurities that may be present in the methanol solution.