Question

1. Составить уравнения предложенных реакций, определить тип реакции. Na + Cl2NaCl H2CO3  CO2 + H2O Fe(OH)3  Fe2O3+ H2O Al + S  Al2S3 AgBr  Ag + Br2 Li2O + H2O  LiOH MgO + H2O  Mg(OH)2 P + O2  P2O5 CH4  C2H2 + H2 KClO3  KCl + O2 KMnO4  K2MnO4 + MnO2 + O2 2. Решить задачи 1. Рассчитать объемы 64 г оксида серы (IV) и 64 г кислорода. 2. Рассчитать, какое количество вещества содержат 90 г воды? 3. Найти массу кислорода в воздухе массой 50 кг, если известно, что массовая доля кислорода в воздухе составляет 20%.Квадратики это стрелки

Answer 1

2Na + Cl2 > 2NaCl
H2CO3 > CO2 + H2O
2Fe(OH)3 > Fe2O3 + 3H2O
2Al + 3S > Al2S3
2AgBr > 2Ag + Br2
Li2O + H2O > 2LiOH
MgO + H2O > Mg(OH)2
4P + 5O2 > 2P2O5
2CH4 > C2H2 + 3H2
2KClO3 > 2KCl + 3O2
2KMnO4 > K2MnO4 + MnO2 +O2
Задачи:
1:     64r               64r
       SO2       /      O2
       64 моль        32 моль
V=Vm * n          
n=m/M
n(SO2)=64/64=1           V(SO2)=22.4*1=22.4л
n(O2)=64/32=0.5          V(O2)=22.4*0.5=11,2л
2: 50/100*20=10кг(О2)

Answer 2

Equations and Reaction Types:

1. Na + Cl2 -> NaCl - This is a combination reaction or synthesis reaction.

2. H2CO3 -> CO2 + H2O - This is a decomposition reaction.

3. Fe(OH)3 -> Fe2O3 + H2O - This is a dehydration reaction or thermal decomposition reaction.

4. Al + S -> Al2S3 - This is a combination reaction or synthesis reaction.

5. AgBr -> Ag + Br2 - This is a displacement reaction or single replacement reaction.

6. Li2O + H2O -> LiOH - This is a neutralization reaction or acid-base reaction.

7. MgO + H2O -> Mg(OH)2 - This is a neutralization reaction or acid-base reaction.

8. P4 + O2 -> P2O5 - This is a combination reaction or synthesis reaction.

9. CH4 -> C2H2 + H2 - This is a decomposition reaction.

10. KClO3 -> KCl + O2 - This is a decomposition reaction.

11. KMnO4 -> K2MnO4 + MnO2 + O2 - This is a disproportionation reaction.

Problem Solving:

1. To calculate the volumes of 64 g of sulfur dioxide (SO2) and 64 g of oxygen (O2), we need to know the molar masses of these substances. The molar mass of SO2 is approximately 64 g/mol, and the molar mass of O2 is approximately 32 g/mol. Using the molar mass, we can calculate the number of moles of each substance:

- Moles of SO2 = Mass of SO2 / Molar mass of SO2 = 64 g / 64 g/mol = 1 mol - Moles of O2 = Mass of O2 / Molar mass of O2 = 64 g / 32 g/mol = 2 mol

Since 1 mole of gas occupies 22.4 liters at standard temperature and pressure (STP), the volumes of 1 mol of SO2 and 2 mol of O2 are both 22.4 liters. Therefore, the volume of 64 g of SO2 and 64 g of O2 would be 22.4 liters each.

2. To calculate the amount of substance (in moles) in 90 g of water (H2O), we need to know the molar mass of water. The molar mass of water is approximately 18 g/mol. Using the molar mass, we can calculate the number of moles of water:

- Moles of H2O = Mass of H2O / Molar mass of H2O = 90 g / 18 g/mol = 5 mol

Therefore, 90 g of water contains 5 moles of water.

3. To find the mass of oxygen in 50 kg of air, given that the mass fraction of oxygen in air is 20%, we can calculate as follows:

- Mass of oxygen = Mass of air * Mass fraction of oxygen - Mass of oxygen = 50 kg * 0.20 = 10 kg

Therefore, there are 10 kg of oxygen in 50 kg of air.

Please let me know if there's anything else I can help you with!