Question

ПОМОГИТЕ С ЗАДАЧЕЙ!!! при обжиге 1 кг известняка, содержащего 10% примесей, получили о,17 м³ углекислого газа. Вычислите объемную долю выхода продукта реакции от теоретически возможного.

Answer 1

Продолжение:
Так как ф*v(теор)=v, то ф = 7,589/9 = 0,843 (или 84,3%)

Answer 2

Calculation of the Volume Fraction of the Reaction Product

To calculate the volume fraction of the reaction product, we need to determine the theoretical volume of the reaction product and compare it to the actual volume obtained.

Given: - Mass of limestone (CaCO3) = 1 kg - Limestone contains 10% impurities - Volume of carbon dioxide (CO2) obtained = 0.17 m³

To calculate the theoretical volume of the reaction product, we need to consider the stoichiometry of the reaction. The balanced chemical equation for the reaction of limestone (CaCO3) with heat to produce carbon dioxide (CO2) is as follows:

CaCO3(s) -> CaO(s) + CO2(g)

From the balanced equation, we can see that 1 mole of CaCO3 produces 1 mole of CO2. The molar mass of CaCO3 is approximately 100.09 g/mol, and the molar mass of CO2 is approximately 44.01 g/mol.

Let's calculate the number of moles of CaCO3 in 1 kg of limestone:

Number of moles of CaCO3 = (mass of CaCO3) / (molar mass of CaCO3) = (1000 g) / (100.09 g/mol) ≈ 9.995 moles

Since the reaction is 1:1 between CaCO3 and CO2, the number of moles of CO2 produced will be the same as the number of moles of CaCO3.

Number of moles of CO2 = 9.995 moles

Now, let's calculate the theoretical volume of CO2 using the ideal gas law:

PV = nRT

Where: P = pressure (assume constant) V = volume n = number of moles R = ideal gas constant T = temperature (assume constant)

Since the pressure and temperature are not provided in the question, we cannot calculate the exact volume. However, we can calculate the volume fraction by comparing the actual volume obtained (0.17 m³) to the theoretical volume.

Volume fraction = (actual volume) / (theoretical volume) * 100%

Let's calculate the theoretical volume of CO2 using the ideal gas law:

The ideal gas constant (R) is approximately 0.0821 L·atm/(mol·K). Assuming a temperature of 298 K and a pressure of 1 atm, we can calculate the theoretical volume:

Theoretical volume of CO2 = (number of moles of CO2) * (R) * (temperature) / (pressure) = (9.995 moles) * (0.0821 L·atm/(mol·K)) * (298 K) / (1 atm) ≈ 24.36 L

Now, let's calculate the volume fraction:

Volume fraction = (actual volume) / (theoretical volume) * 100% = (0.17 m³) / (24.36 L) * 100% ≈ 0.697%

Therefore, the volume fraction of the reaction product (CO2) obtained from the given reaction is approximately 0.697% of the theoretical volume.

Please note that the above calculation assumes ideal conditions and may not account for all factors that could affect the reaction.