Question

Какую массу металлического натрия необходимо растворить в 200 мл 10% раствора гидроксида натрия (p=1,1 г/мл), чтобы концентрация вещества в растворе возросла до 30%?

Answer 1

Проверьте правильность ответа: к числителю (22 грамма) добавьте полученную массу и к знаменателю (220 грамм) также добавьте найденную массу и вы в самом деле получите ω₂ = 0,3

Answer 2

Calculation of the Mass of Sodium Metal

To calculate the mass of metallic sodium needed to dissolve in a 200 ml 10% solution of sodium hydroxide (with a density of 1.1 g/ml) in order to increase the concentration of the solution to 30%, we can use the following steps:

1. Determine the initial mass of the sodium hydroxide solution: - The initial volume of the solution is 200 ml. - The initial concentration of the solution is 10%. - The density of the solution is 1.1 g/ml. - Therefore, the initial mass of the solution can be calculated as follows: ``` Initial mass of solution = Initial volume of solution * Density of solution = 200 ml * 1.1 g/ml = 220 g ```

2. Determine the final mass of the sodium hydroxide solution: - The final volume of the solution is still 200 ml. - The final concentration of the solution is 30%. - Therefore, the final mass of the solution can be calculated as follows: ``` Final mass of solution = Final volume of solution * Final concentration of solution = 200 ml * 30% = 60 g ```

3. Calculate the mass of sodium needed to achieve the desired concentration increase: - The mass of sodium needed can be calculated by subtracting the final mass of the solution from the initial mass of the solution: ``` Mass of sodium = Final mass of solution - Initial mass of solution = 60 g - 220 g = -160 g ```

Based on the calculations, it appears that a negative mass of sodium is obtained. This suggests that it is not possible to achieve a 30% concentration in the solution by dissolving metallic sodium in the given 10% solution of sodium hydroxide. Please double-check the provided information and calculations to ensure accuracy.

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