Question

Определите массу амониака,добытого при взаимодействии 14г.азота с достаточным количеством водорода.

Answer 1

Это вещество назвывает аммиак! Аммоний - это ион.

N2 + 3H2 = 2NH3

n(N2) = m(N2)/M(N2) = 14/14 = 1 моль

n(NH3) = 2*n(N2) = 2*1 = 2 моль

m(NH3) = n(NH3)*M(NH3) = 2*17 = 34 г.

 

Answer 2

Уравнение реакции:N2 + 3H2 = 2NH3

n(N2) = m(N2):M(N2) = 14:14 = 1 моль

n(NH3) = 2*n(N2) = 2*1 = 2 моль

m(NH3) = n(NH3)*M(NH3) = 2*17 = 34 г.

Ответ:34 г.

Answer 3

Calculating the Mass of Ammonia Produced

To calculate the mass of ammonia produced when 14g of nitrogen reacts with a sufficient amount of hydrogen, we can use the balanced chemical equation for the formation of ammonia from nitrogen and hydrogen:

N2 + 3H2 → 2NH3

According to the balanced chemical equation, 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

Step 1: Calculate the Moles of Nitrogen

To find the moles of nitrogen, we use the formula:

moles = mass / molar mass

The molar mass of nitrogen (N2) is 28.02 g/mol.

So, the moles of nitrogen = 14g / 28.02 g/mol = 0.4996 moles

Step 2: Calculate the Moles of Ammonia

From the balanced chemical equation, 1 mole of nitrogen produces 2 moles of ammonia.

So, the moles of ammonia produced = 0.4996 moles * 2 = 0.9992 moles

Step 3: Calculate the Mass of Ammonia

Finally, we can calculate the mass of ammonia produced using the formula:

mass = moles * molar mass

The molar mass of ammonia (NH3) is 17.03 g/mol.

Therefore, the mass of ammonia produced = 0.9992 moles * 17.03 g/mol = 17.01g

So, the mass of ammonia produced when 14g of nitrogen reacts with a sufficient amount of hydrogen is approximately 17.01 grams.