Question

а)оксид железа(3)+алюминий------------>б)оксид железа(3)+водород------------->в)хлорид меди(2)+алюминий-------->г)оксид свинца(4)+углерод-------------->д)бромид железа(3)+хлор----------->помогите не помню

Answer 1

а) Fe2O3+2Al=Al2O3+2Fe

б) Fe2O3 + 3H2 = 2Fe + 3H2O

в) 3CuCl2 + 2Al = 2AlCl3 + 3Cu

г) PbO2 + C = Pb + CO2

д) 2FeBr3 + 3Cl2 = 2FeCl3 + 3Br2

Answer 2

Chemical Reactions

a) оксид железа(3) + алюминий

The reaction between iron(III) oxide and aluminum is a type of thermite reaction. In this reaction, aluminum reduces iron(III) oxide to produce molten iron and aluminum oxide. The balanced chemical equation for this reaction is:

2 Fe2O3(s) + 2 Al(s) → 2 Fe(l) + Al2O3(s)

This reaction is highly exothermic and is often used in welding and metal cutting due to the high temperatures it produces. b) оксид железа(3) + водород

Iron(III) oxide does not react with hydrogen under normal conditions. The reaction between iron(III) oxide and hydrogen to produce iron and water does not occur spontaneously. Therefore, this reaction is not feasible under standard conditions. в) хлорид меди(2) + алюминий

When aluminum is added to copper(II) chloride, a single displacement reaction occurs. The balanced chemical equation for this reaction is:

2 Al(s) + 3 CuCl2(aq) → 2 AlCl3(aq) + 3 Cu(s)

In this reaction, aluminum displaces copper from copper(II) chloride, forming aluminum chloride and copper metal. г) оксид свинца(4) + углерод

The reaction between lead(IV) oxide and carbon is a reduction reaction. The balanced chemical equation for this reaction is:

PbO2(s) + C(s) → Pb(l) + CO2(g)

In this reaction, carbon reduces lead(IV) oxide to produce lead metal and carbon dioxide. д) бромид железа(3) + хлор

Iron(III) bromide does not react with chlorine under normal conditions. The reaction between iron(III) bromide and chlorine to produce iron(III) chloride and bromine does not occur spontaneously. Therefore, this reaction is not feasible under standard conditions. I hope this helps! If you have further questions, feel free to ask.