Question

1) KMnO4+KI+H2SO4=>Mn(2+) , I2 2)KMnO4+KI+H2O=>MnO2, I2овр

Answer 1

1. 2KMn(+7)O4 + 10KI(-) + 8H2SO4 = 2Mn(+2)SO4 + 6K2SO4 + 5I2(0) + 8H2OMn^+7
$Mn^+^7 + 5e --\ \textgreater \ Mn^+^2$                                    |      | 2  
                                                                                  | 10 |      
$2I^-^1 - 2e --\ \textgreater \ I_{2}^0$                                               |      | 5
$Mn^+^7$ в KMnO4 - окислитель, $2I^-^1$ в KI - восстановитель
2. 2KMn(+7)O4 + 6KI(-) + 4H2O = 2Mn(+4)O2 + 8KOH + 3I2(0)
$Mn^+^7 + 3e --\ \textgreater \ Mn^+^4$                                     |    | 2
                                                                                  | 6 |
$2I^-^1 - 2e --\ \textgreater \ I_{2}^0$                                                |    | 3
$Mn^+^7$ в KMnO4 - окислитель, $2I^-^1$ в KI - восстановитель

Answer 2

Chemical Reaction Equations

The chemical equations you've provided represent redox reactions involving potassium permanganate (KMnO4), potassium iodide (KI), and sulfuric acid (H2SO4). Let's break down each reaction separately.

1. KMnO4 + KI + H2SO4 → Mn(2+) + I2 This equation represents the reaction of potassium permanganate, potassium iodide, and sulfuric acid. The products of this reaction are manganese(II) ions (Mn(2+)) and elemental iodine (I2).

2. KMnO4 + KI + H2O → MnO2 + I2

This equation represents the reaction of potassium permanganate, potassium iodide, and water. The products of this reaction are manganese dioxide (MnO2) and elemental iodine (I2).

Explanation

In the first reaction, the sulfuric acid likely serves as a source of protons (H+) to facilitate the redox reaction. The permanganate ion (MnO4-) is a strong oxidizing agent and can oxidize iodide ions (I-) to elemental iodine (I2). The manganese(II) ions (Mn(2+)) are the reduced form of the permanganate ion.

In the second reaction, the presence of water leads to the formation of manganese dioxide (MnO2) as a product. This reaction also results in the formation of elemental iodine (I2) from the oxidation of iodide ions by the permanganate ion.

Conclusion

These reactions demonstrate the redox properties of potassium permanganate and its ability to oxidize other substances, such as iodide ions, resulting in the formation of different products depending on the reaction conditions.