Question

Масса оксида углерода (IV), полученная при сгорании 0,1 моль метана (СН4)

Answer 1

CH4 + 2O2 ----> CO2 + 2H2O
n(CH4) = n(CO2) = 5 моль
m(CO2) = 5 моль * 44 г / моль = 220 г 
Ответ: 220 г

Answer 2

CH4+2O2->CO2+2H2O
Коэффициенты у метана и углекислого газа равны, поэтому здесь 0.1 моль СО2, m(CO2)=0,1*44=4,4 г

Answer 3

Calculating the Mass of Carbon Dioxide (IV) Produced from the Combustion of 0.1 Moles of Methane (CH4)

To calculate the mass of carbon dioxide (IV) produced from the combustion of 0.1 moles of methane (CH4), we can use the balanced chemical equation for the combustion of methane:

CH4 + 2O2 → CO2 + 2H2O

From the balanced equation, we can see that 1 mole of methane produces 1 mole of carbon dioxide. Therefore, the mass of carbon dioxide produced can be calculated using the molar mass of carbon dioxide.

The molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.

Calculation:

Using the given information: - Moles of methane (CH4) = 0.1

We can calculate the mass of carbon dioxide (IV) produced as follows:

Mass of CO2 = Moles of CH4 × Molar mass of CO2 Mass of CO2 = 0.1 moles × 44.01 g/mol Mass of CO2 = 4.401 g

Therefore, the mass of carbon dioxide (IV) produced from the combustion of 0.1 moles of methane is approximately 4.401 grams.