Question

Рассчитайте количество вещества сульфата бария, выпавшего в осадок при взаимодействии 3,5 моль хлорида бария с раствором серной кислоты.

Answer 1

По стехиометрии в уравнении реакции (см. приложение) количество вещества хлорида бария равно количеству вещества сульфата бария, т. е. равно 3,5 моль.

Answer 2

Количество будет то же 3,5 моль

Answer 3

Calculating the Amount of Barium Sulfate Precipitated

To calculate the amount of barium sulfate precipitated when 3.5 moles of barium chloride reacts with sulfuric acid, we can use the stoichiometry of the reaction to determine the amount of barium sulfate formed.

The balanced chemical equation for the reaction between barium chloride and sulfuric acid is:

BaCl2 + H2SO4 → BaSO4 + 2HCl

From the balanced equation, we can see that 1 mole of barium chloride reacts with 1 mole of sulfuric acid to produce 1 mole of barium sulfate.

Therefore, when 3.5 moles of barium chloride react with sulfuric acid, the amount of barium sulfate formed will also be 3.5 moles.

So, the amount of barium sulfate precipitated is 3.5 moles.