Question

амоний хлорил массой 50 г смешали с 40 г кальций гидрооксида и нагрели. Определить массу образованного газа.

Answer 1

2NH4Cl + Ca(OH)2 ==> 2NH3 + 2 H2O + CaCl2

Ca(OH)2 - в избытке, так как его моль равна 0,54, а моли NH4CL равны 0,467

Моли считаются по формуле массу делить на молярную массе.

Газ - NH3

Тогда считаем массу газа по NH4Cl пропорцией. Молярная масса NH3 равна 17, но у нас их две молекулы, тогда ещё нам нужно умножить на 2, т.е. получится 34. 53,5 - молекулярная масса NH4CL

m(NH3) = 50*54/2*53,5 = 15,89

Answer 2

Calculation of the Mass of the Gas Produced

To determine the mass of the gas produced when 50 g of ammonium chloride (NH4Cl) is mixed with 40 g of calcium hydroxide (Ca(OH)2) and heated, we need to consider the balanced chemical equation for the reaction between ammonium chloride and calcium hydroxide.

The balanced chemical equation for the reaction is as follows: 2NH4Cl + Ca(OH)2 → 2NH3 + 2H2O + CaCl2

According to the balanced equation, for every 2 moles of NH4Cl reacted, 2 moles of NH3 gas are produced. Therefore, we need to calculate the number of moles of NH4Cl and then use the stoichiometry of the balanced equation to determine the mass of NH3 gas produced.

Calculation Steps:

1. Calculate the number of moles of NH4Cl: - The molar mass of NH4Cl is 53.49 g/mol (14.01 g/mol for nitrogen + 4 * 1.01 g/mol for hydrogen + 35.45 g/mol for chlorine). - The number of moles of NH4Cl is calculated by dividing the mass of NH4Cl by its molar mass