
Какое количество вещества составляют 66 г оксида углерода (IV)?


Ответы на вопрос

n= m\Mr
n= 66\44=1.5 моль



Количество вещества оксида углерода (IV)
Количество вещества оксида углерода (IV) весит 66 г.
Unfortunately, I couldn't find a specific snippet that directly answers the question. However, I can provide you with some general information about calculating the amount of substance.
The amount of substance is measured in moles, which is a unit used to count atoms, molecules, or ions. One mole of any substance contains Avogadro's number of particles, which is approximately 6.022 x 10^23 particles.
To calculate the amount of substance, you can use the formula:
Amount of substance (in moles) = Mass (in grams) / Molar mass (in g/mol)
In this case, we need to know the molar mass of carbon dioxide (CO2), which is the chemical formula for carbon dioxide.
The molar mass of carbon dioxide (CO2) is calculated by adding up the atomic masses of carbon (C) and oxygen (O). The atomic mass of carbon is approximately 12.01 g/mol, and the atomic mass of oxygen is approximately 16.00 g/mol.
Therefore, the molar mass of carbon dioxide (CO2) is:
Molar mass of CO2 = (12.01 g/mol) + 2 * (16.00 g/mol) = 44.01 g/mol
Now we can calculate the amount of substance of carbon dioxide (CO2) using the given mass of 66 g:
Amount of substance (in moles) = 66 g / 44.01 g/mol
Calculating this, we find that the amount of substance of carbon dioxide (CO2) is approximately 1.50 moles.
Please note that the calculation assumes that the given substance is pure carbon dioxide (CO2) and that the molar mass values used are accurate.
I hope this helps! Let me know if you have any further questions.


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