Question

Вычислите массу соли, полученную при взаимодействии 126 г оксида кальция и азотной кислоты, если практический выход 80% от теоретического

Answer 1

Дано:
m(CaO) = 126 г
η(соли) = 80%=0,8
m(соли)-?
M(CaO) = 56 г/моль
M(Ca(NO3)2) = 164 г/моль
126 г ---------------   х г
СаО + 2HNO3 = Ca(NO3)2 + H2O
56 г    ---------------- 164 г
х=m'(Ca(NO3)2) = 126 г*164 г/56 г = 369 г - это масса при 100% выходе
m(Ca(NO3)2) = m'(Ca(NO3)2)*η(Ca(NO3)2)
m(Ca(NO3)2) = 369 г*0,8 = 295,2 г
Ответ: 295,2 г нитрата кальция

Answer 2

Calculating the Mass of Salt Produced

To calculate the mass of salt produced when 126g of calcium oxide reacts with nitric acid, we can use the following chemical equation for the reaction:

CaO + 2HNO3 → Ca(NO3)2 + H2O

The molar mass of CaO is 56.08 g/mol, and the molar mass of HNO3 is 63.01 g/mol. From the balanced chemical equation, we can see that 1 mole of CaO reacts with 2 moles of HNO3 to produce 1 mole of Ca(NO3)2.

Given that the practical yield is 80% of the theoretical yield, we can calculate the mass of salt produced using this information.

Using the molar masses and the stoichiometry of the reaction, we can calculate the mass of salt produced.

The molar mass of Ca(NO3)2 is 164.09 g/mol.

Calculation

Using the given information and the stoichiometry of the reaction, we can calculate the mass of salt produced as follows:

1. Calculate the moles of CaO: - Moles of CaO = Mass of CaO / Molar mass of CaO - Moles of CaO = 126g / 56.08 g/mol - Moles of CaO = 2.24 moles

2. Calculate the moles of Ca(NO3)2 produced: - Moles of Ca(NO3)2 = Moles of CaO (from the balanced equation) - Moles of Ca(NO3)2 = 2.24 moles

3. Calculate the theoretical mass of Ca(NO3)2: - Theoretical mass = Moles of Ca(NO3)2 * Molar mass of Ca(NO3)2 - Theoretical mass = 2.24 moles * 164.09 g/mol - Theoretical mass = 367.22g

4. Calculate the practical mass of Ca(NO3)2: - Practical mass = Theoretical mass * Yield - Practical mass = 367.22g * 0.80 - Practical mass = 293.78g

Answer

The mass of salt, Ca(NO3)2, obtained from the reaction is 293.78 grams.