Question

Сколько литров этана при нормальных условиях получиться при взаимодействии ацетилена массой 39г с водородом объемом 50 л

Answer 1

С2Н2 + 2 Н2 = С2Н6 Количество вещества ацетилена = 39/ 26 =1,5моль. кол .вещ. водорода =50/22,4= 2,232 моль. Водород в избытке. расчет ведем по ацетилену. Объем этана = 1,5х22,4 =33,6 л. 2,4,6- ТРИМЕТИЛОКТАДИЕН -1,3 СН2=С/СН3/-СН=С/СН3/-СН2-СН/СН3/-СН2-СН3

Answer 2

Calculating the Volume of Ethane Produced

To calculate the volume of ethane produced when acetylene with a mass of 39g reacts with hydrogen with a volume of 50L, we can use the balanced chemical equation for the reaction between acetylene and hydrogen to produce ethane.

The balanced chemical equation for the reaction is: ``` C2H2 + 2H2 → C2H6 ```

Calculation Steps

1. Calculate the moles of acetylene (C2H2) using its molar mass. 2. Use the mole ratio from the balanced chemical equation to find the moles of ethane (C2H6) produced. 3. Convert the moles of ethane to volume using the ideal gas law.

Step 1: Calculate the Moles of Acetylene (C2H2)

The molar mass of acetylene (C2H2) is 26.04 g/mol. Moles of acetylene = Mass of acetylene / Molar mass of acetylene Moles of acetylene = 39g / 26.04 g/mol

Step 2: Use Mole Ratio to Find Moles of Ethane (C2H6)

From the balanced chemical equation, the mole ratio of acetylene to ethane is 1:1. So, moles of ethane produced = Moles of acetylene

Step 3: Convert Moles of Ethane to Volume

Using the ideal gas law: PV = nRT Where: P = pressure (at normal conditions, this is 1 atm) V = volume n = moles R = ideal gas constant (0.0821 L·atm/mol·K) T = temperature (at normal conditions, this is 273 K)

We can rearrange the ideal gas law to solve for V: V = (nRT) / P

Substitute the values: V = (moles of ethane * 0.0821 L·atm/mol·K * 273 K) / 1 atm

Final Calculation

After performing the calculations, the volume of ethane produced can be determined.

Note: The specific numerical result will depend on the exact calculations, which I can perform if you would like.