Question

Смешали при нормальных условиях 1,12л Cl2 и 2,24 л H2 . смесь подожгли. КАкой объем хлорида водорода образуеться

Answer 1

H2+CL2=2HCL

По уравнению видно  водород и хлор реагирут в отношении 1/1, следовательно объем водорода в избытке, считаем по хлору .  по уравнеию видно , что на  1 моль Хлора приходиться 2 моль хлолроводорода, следовательно объем полученного хлороводорода равен 2,24 л. 

Answer 2

Calculation of Hydrogen Chloride Volume

To calculate the volume of hydrogen chloride (HCl) formed when 1.12 liters of chlorine gas (Cl2) and 2.24 liters of hydrogen gas (H2) are mixed and ignited, we need to use the balanced chemical equation for the reaction between chlorine and hydrogen:

Cl2 + H2 → 2HCl

According to the balanced equation, 1 mole of chlorine reacts with 1 mole of hydrogen to produce 2 moles of hydrogen chloride. To determine the volume of hydrogen chloride formed, we need to convert the given volumes of chlorine and hydrogen gases into moles and then use the stoichiometry of the balanced equation.

First, let's convert the volumes of chlorine and hydrogen gases into moles using the ideal gas law:

n = V / Vm

where: - n is the number of moles - V is the volume of the gas - Vm is the molar volume at standard temperature and pressure (STP), which is 22.4 liters/mol for gases

For chlorine gas: n(Cl2) = 1.12 L / 22.4 L/mol = 0.05 mol

For hydrogen gas: n(H2) = 2.24 L / 22.4 L/mol = 0.1 mol

Now that we have the number of moles of chlorine and hydrogen, we can determine the limiting reactant. The limiting reactant is the one that is completely consumed in the reaction and determines the maximum amount of product that can be formed.

From the balanced equation, we can see that 1 mole of chlorine reacts with 1 mole of hydrogen to produce 2 moles of hydrogen chloride. Therefore, the stoichiometric ratio between chlorine and hydrogen chloride is 1:2.

Since we have 0.05 moles of chlorine and 0.1 moles of hydrogen, we can see that the chlorine is the limiting reactant because it is present in a smaller amount. This means that all of the chlorine will be consumed in the reaction, and the amount of hydrogen chloride formed will be determined by the amount of chlorine.

Using the stoichiometry of the balanced equation, we can calculate the moles of hydrogen chloride formed:

n(HCl) = 2 * n(Cl2) = 2 * 0.05 mol = 0.1 mol

Finally, we can convert the moles of hydrogen chloride into volume using the ideal gas law:

V(HCl) = n(HCl) * Vm = 0.1 mol * 22.4 L/mol = 2.24 L

Therefore, when 1.12 liters of chlorine gas and 2.24 liters of hydrogen gas are mixed and ignited, the volume of hydrogen chloride formed is 2.24 liters.