Question

Найти массу хлорида железа(3), образующегося при растворении 1,6 г оксида железа(3) в соляной кислоте

Answer 1

Fe2O3+6HCI=2FeCI3+3H2O
Mr()Fe2O3)=160г/моль
n(Fe2O3)=m/Mr=1,6/160=0,01молб
По уравнению FeCI3 в 2 раза больше чем Fe2O3
n(FeCI3)=0,01*2=0,02моль
M(FeCI3)=0,02*Mr(FeCI2) 162,5=3,25грамм

Ответ масса FeCI3 = 162,5гр

Answer 2

Calculating the Mass of Iron(III) Chloride Formed

To find the mass of iron(III) chloride formed when 1.6 g of iron(III) oxide is dissolved in hydrochloric acid, we can use the following chemical equation:

Fe2O3(s) + 6HCl(aq) → 2FeCl3(aq) + 3H2O(l)

According to the equation, 1 mole of iron(III) oxide reacts with 6 moles of hydrochloric acid to produce 2 moles of iron(III) chloride.

Steps to Calculate the Mass:

1. Calculate the moles of iron(III) oxide: - Molar mass of Fe2O3 = 2*55.85 + 3*16.00 = 159.7 g/mol - Moles of Fe2O3 = Mass / Molar mass = 1.6 g / 159.7 g/mol

2. Use the mole ratio from the balanced chemical equation to find the moles of iron(III) chloride: - Moles of FeCl3 = Moles of Fe2O3 * (2 moles FeCl3 / 1 mole Fe2O3)

3. Calculate the mass of iron(III) chloride: - Mass of FeCl3 = Moles of FeCl3 * Molar mass of FeCl3

Calculation:

1. Moles of Fe2O3: - Moles of Fe2O3 = 1.6 g / 159.7 g/mol = 0.0100 mol 2. Moles of FeCl3: - Moles of FeCl3 = 0.0100 mol * (2 moles FeCl3 / 1 mole Fe2O3) = 0.0200 mol

3. Mass of FeCl3: - Molar mass of FeCl3 = 162.20 g/mol (from a reliable source not provided in the search results) - Mass of FeCl3 = 0.0200 mol * 162.20 g/mol = 3.24 g

Answer:

The mass of iron(III) chloride formed when 1.6 g of iron(III) oxide is dissolved in hydrochloric acid is 3.24 grams.