Question

Найти массу хлорида натрия полученную при взаимодействии 31г оксида натрия с соляной кислотой

Answer 1

31 г                            х
Na2O   +   2HCl   =  2NaCl   +  H2O
1 моль                    2 моль
М=62 г/моль          М=58,5 г/моль
n=31/62=0,5 моль
По уравнению реакции хлорида натрия образуется в 2 раза больше, чем вступает в реакцию оксида натрия, поэтому
n(NaCl) = 2*n(Na2O) = 2*0,5 = 1 моль
m(NaCl) = M*n = 58,5*1 = 58,5 г

Answer 2

Calculating the Mass of Sodium Chloride Produced

To find the mass of sodium chloride (NaCl) produced when 31g of sodium oxide (Na2O) reacts with hydrochloric acid (HCl), we can use the balanced chemical equation for the reaction and the stoichiometry of the reaction.

The balanced chemical equation for the reaction is: Na2O + 2HCl → 2NaCl + H2O

From the balanced chemical equation, we can see that 1 mole of Na2O reacts with 2 moles of HCl to produce 2 moles of NaCl.

Using the molar masses: - The molar mass of Na2O is 61.98 g/mol. - The molar mass of HCl is 36.46 g/mol.

We can calculate the mass of NaCl produced as follows:

1. Calculate the moles of Na2O: - Moles of Na2O = Mass of Na2O / Molar mass of Na2O - Moles of Na2O = 31g / 61.98 g/mol - Moles of Na2O ≈ 0.50 moles

2. Use the mole ratio from the balanced chemical equation to find moles of NaCl produced: - Moles of NaCl = Moles of Na2O × (2 moles of NaCl / 1 mole of Na2O) - Moles of NaCl = 0.50 moles × 2 - Moles of NaCl = 1.00 moles

3. Calculate the mass of NaCl produced: - Mass of NaCl = Moles of NaCl × Molar mass of NaCl - Mass of NaCl = 1.00 moles × 58.44 g/mol - Mass of NaCl ≈ 58.44 grams

Conclusion

The mass of sodium chloride produced when 31g of sodium oxide reacts with hydrochloric acid is approximately 58.44 grams.