Question

Определите возможность самопроизвольного протекания реакции при 298 к: Fe(OH)2+H2SO4=FeSO4+H2O

Answer 1

 держи, спрашивай если что

Answer 2

Spontaneous Reaction at 298 K: Fe(OH)2 + H2SO4 = FeSO4 + H2O

At 298 K, the spontaneity of a reaction can be determined by considering the change in Gibbs free energy (ΔG) for the reaction. If the ΔG is negative, the reaction is spontaneous at that temperature.

The equation for the change in Gibbs free energy (ΔG) is given by the formula: ΔG = ΔH - TΔS Where: - ΔH is the change in enthalpy - T is the temperature in Kelvin - ΔS is the change in entropy

To determine the spontaneity of the reaction Fe(OH)2 + H2SO4 = FeSO4 + H2O at 298 K, we need the enthalpy change (ΔH) and the entropy change (ΔS) for the reaction.

Unfortunately, the search results provided do not contain specific enthalpy or entropy values for the reaction Fe(OH)2 + H2SO4 = FeSO4 + H2O at 298 K. Therefore, it's not possible to calculate the spontaneity of the reaction based on the given information.

If you have access to the enthalpy and entropy values for the reaction at 298 K, you can use the formula mentioned above to calculate the change in Gibbs free energy (ΔG) and determine the spontaneity of the reaction.