Question

Какой объем займет при нормальных условиях 11 Г углекислого газа?

Answer 1

Молярная масса СО2 = 44г/ моль .Количество вещества СО2 =11/44 = 0,25 моль Объем СО2 = 22,4Х0,25 =5,6л .Один моль любого газа при нормальных условиях занимают объем.равный 22,4.л. 

Answer 2

Volume of 11 G of Carbon Dioxide at Standard Conditions

Under normal conditions, the volume of 11 grams of carbon dioxide can be calculated using the ideal gas law equation, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.

Using the molar mass of carbon dioxide (44.01 g/mol), we can calculate the number of moles of carbon dioxide in 11 grams.

Calculation: 1. Calculate the number of moles of carbon dioxide: - Number of moles = Mass / Molar mass - Number of moles = 11 g / 44.01 g/mol - Number of moles ≈ 0.25 moles

2. Use the ideal gas law to find the volume at standard conditions: - P = 1 atm (standard pressure) - T = 273 K (standard temperature) - R = 0.0821 L·atm/(K·mol) (ideal gas constant)

- V = (nRT) / P - V = (0.25 moles * 0.0821 L·atm/(K·mol) * 273 K) / 1 atm - V ≈ 5.65 liters

Therefore, the volume of 11 grams of carbon dioxide at standard conditions is approximately 5.65 liters