Question

определите количество вещества и объем при нормальных условиях соляной кислоты массой 73 грамма

Answer 1

Дано:

m(HCl) - 73г.

Найти:

n(HCl) - ?

V(HCl) - ?

Решение:

n(HCl)=m/M

M(HCl)=1+35,5=36,5 г/моль

n(HCl)=73/36,5=2 моль

V(HCl)=Vm*n=22.4*2=44.8 л

 

Answer 2

Calculation of the Amount of Substance and Volume of Hydrochloric Acid

To determine the amount of substance and volume of hydrochloric acid at normal conditions, we need to use the given mass of 73 grams.

The molar mass of hydrochloric acid (HCl) is approximately 36.46 grams per mole To calculate the amount of substance (in moles), we divide the given mass by the molar mass:

Amount of Substance (n) = Mass / Molar Mass

Substituting the values, we have:

n = 73 g / 36.46 g/mol

Calculating this, we find that the amount of substance of hydrochloric acid is approximately 2 moles.

Next, we can use the ideal gas law to calculate the volume of the hydrochloric acid at normal conditions. The ideal gas law equation is:

PV = nRT

Where: - P is the pressure (at normal conditions, it is 1 atmosphere or 101.325 kilopascals) - V is the volume - n is the amount of substance (in moles) - R is the ideal gas constant (0.0821 L·atm/(mol·K)) - T is the temperature (at normal conditions, it is 273.15 Kelvin)

Rearranging the equation to solve for V, we have:

V = nRT / P

Substituting the values, we get:

V = 2 mol * 0.0821 L·atm/(mol·K) * 273.15 K / 101.325 kPa

Calculating this, we find that the volume of hydrochloric acid at normal conditions is approximately 4.67 liters.

Therefore, the amount of substance of hydrochloric acid with a mass of 73 grams is approximately 2 moles, and its volume at normal conditions is approximately 4.67 liters.

Please note that these calculations are based on ideal gas behavior and assume that the hydrochloric acid behaves as an ideal gas at normal conditions.

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