Question

Мрамор (caco3) обработали раствором соляной кислоты (Hcl) vfccjq 7 , 3 г по уравнению реакции : СACO3+HCL---CACL2+H2O+CO2 какова масса и количество вещества выделившегося газа ?

Answer 1

СaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
ν(HCl) = m/M = 7,3 / 36,5 = 0,2 моль
ν(CO₂) = 0,5ν(HCl) = 0,1 моль
m(CO₂) = νM = 44·0,1 = 4,4 г
Ответ: ν(CO₂) = 0,1 моль; m(CO₂) = 4,4 г.

Answer 2

Reaction Equation and Stoichiometry

The reaction equation for the reaction between calcium carbonate (CaCO3) and hydrochloric acid (HCl) is as follows:

CaCO3 + 2HCl → CaCl2 + H2O + CO2

According to the balanced equation, 1 mole of calcium carbonate reacts with 2 moles of hydrochloric acid to produce 1 mole of calcium chloride, 1 mole of water, and 1 mole of carbon dioxide.

Calculation of Gas Mass and Amount

To calculate the mass and amount of gas (carbon dioxide) produced, we need to know the mass of calcium carbonate reacted. In this case, the mass of calcium carbonate is given as 3 grams.

To find the amount of calcium carbonate in moles, we can use its molar mass. The molar mass of calcium carbonate (CaCO3) is calculated as follows:

1 atom of calcium (Ca) has a molar mass of approximately 40.08 g/mol. 1 atom of carbon (C) has a molar mass of approximately 12.01 g/mol. 3 atoms of oxygen (O) have a combined molar mass of approximately 3 x 16.00 g/mol = 48.00 g/mol.

Adding up these masses, we get: 40.08 g/mol (Ca) + 12.01 g/mol (C) + 48.00 g/mol (3 O) = 100.09 g/mol (CaCO3)

Now, we can calculate the amount of calcium carbonate in moles using the given mass of 3 grams: Amount of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3 Amount of CaCO3 = 3 g / 100.09 g/mol ≈ 0.02998 mol (rounded to 5 decimal places)

According to the stoichiometry of the reaction, 1 mole of calcium carbonate produces 1 mole of carbon dioxide. Therefore, the amount of carbon dioxide produced is also approximately 0.02998 moles.

To calculate the mass of carbon dioxide produced, we can use its molar mass. The molar mass of carbon dioxide (CO2) is calculated as follows:

1 atom of carbon (C) has a molar mass of approximately 12.01 g/mol. 2 atoms of oxygen (O) have a combined molar mass of approximately 2 x 16.00 g/mol = 32.00 g/mol.

Adding up these masses, we get: 12.01 g/mol (C) + 32.00 g/mol (2 O) = 44.01 g/mol (CO2)

Now, we can calculate the mass of carbon dioxide produced using the amount of carbon dioxide in moles: Mass of CO2 = Amount of CO2 x Molar mass of CO2 Mass of CO2 = 0.02998 mol x 44.01 g/mol ≈ 1.319 g (rounded to 3 decimal places)

Therefore, the mass of carbon dioxide produced is approximately 1.319 grams.

To summarize: - The amount of carbon dioxide produced is approximately 0.02998 moles. - The mass of carbon dioxide produced is approximately 1.319 grams.

Please note that these calculations are based on the given information and assumptions about the reaction conditions.