Question

Дам 100баллов. Напишите в ионной форме уравнения реакций, расставьте коэффициенты. 1)Mg(No3)2+NaCI->MgCI2+NaNo32)Ca(OH)2+HCI->CaCI2+H2O 3) CuSo4+KOH->Cu(OH)2+K2sօ4 4) K2Co3+NaSo4->K2So4+Na2Co3 Помогите, пожалуйста. Буду очень благодарна.

Answer 1

Ловите, желаю вам удачи

Answer 2

Mg(NO3)2 + 2NaCl ⇄ MgCl2 + 2NaNO3
Mg²⁺+2NO₃⁻+2Na⁺+2Cl⁻ = Mg²⁺+2Cl⁻+2Na⁺+2NO₃⁻
Данная реакция не идет.
2) 
Ca(OH)₂ + 2HCl = CaCl2 + 2H₂O
Ca²⁺+2OH⁻+2H⁺+2Cl⁻ = Ca²⁺+2Cl⁻ + 2H₂O
2H⁺+2OH⁻=2H₂O
H⁺+OH⁻=H₂O
3)
CuSO₄ + 2KOH = Cu(OH)₂↓ + K₂SO₄
Cu²⁺+SO₄²⁻+2K⁺+2OH⁻=Cu(OH)₂↓+2K⁺+SO₄²⁻
Cu²⁺+2OH⁻ = Cu(OH)₂↓
4)
K₂CO₃ + Na₂SO₄ = K₂SO₄ + Na₂CO₃
2K⁺+CO₃²⁻+2Na⁺+SO₄²⁻ = 2K⁺+SO₄⁻+2Na⁺+CO₃²⁻
Данная реакция не идет

Answer 3

Balancing Chemical Equations

Sure, I'd be happy to help you with balancing these chemical equations. Let's start with the first one.

1) Balancing the equation: Mg(NO3)2 + NaCl -> MgCl2 + NaNO3

First, let's count the atoms on each side of the equation: - Mg: 1 (left), 1 (right) - N: 2 (left), 1 (right) - O: 6 (left), 3 (right) - Na: 1 (left), 1 (right) - Cl: 2 (left), 2 (right)

To balance the equation, we can start by adding coefficients to the compounds: Mg(NO3)2 + 2NaCl -> MgCl2 + 2NaNO3

Now, let's check the balance: - Mg: 1 (left), 1 (right) - N: 2 (left), 2 (right) - O: 6 (left), 6 (right) - Na: 2 (left), 2 (right) - Cl: 2 (left), 2 (right)

The equation is now balanced.

2) Balancing the equation: Ca(OH)2 + HCl -> CaCl2 + H2O

First, let's count the atoms on each side of the equation: - Ca: 1 (left), 1 (right) - O: 2 (left), 1 (right) - H: 2 (left), 2 (right) - Cl: 1 (left), 2 (right)

To balance the equation, we can add coefficients: Ca(OH)2 + 2HCl -> CaCl2 + 2H2O

Now, let's check the balance: - Ca: 1 (left), 1 (right) - O: 2 (left), 2 (right) - H: 4 (left), 4 (right) - Cl: 2 (left), 2 (right)

The equation is now balanced.

3) Balancing the equation: CuSO4 + KOH -> Cu(OH)2 + K2SO4

First, let's count the atoms on each side of the equation: - Cu: 1 (left), 1 (right) - O: 4 (left), 2 (right) - H: 2 (left), 2 (right) - K: 1 (left), 2 (right) - S: 1 (left), 1 (right)

To balance the equation, we can add coefficients: CuSO4 + 2KOH -> Cu(OH)2 + K2SO4

Now, let's check the balance: - Cu: 1 (left), 1 (right) - O: 4 (left), 4 (right) - H: 2 (left), 2 (right) - K: 2 (left), 2 (right) - S: 1 (left), 1 (right)

The equation is now balanced.

4) Balancing the equation: K2CO3 + Na2SO4 -> K2SO4 + Na2CO3

First, let's count the atoms on each side of the equation: - K: 2 (left), 2 (right) - C: 1 (left), 1 (right) - O: 3 (left), 3 (right) - Na: 2 (left), 2 (right) - S: 1 (left), 1 (right)

To balance the equation, we can add coefficients: K2CO3 + Na2SO4 -> K2SO4 + Na2CO3

Now, let's check the balance: - K: 2 (left), 2 (right) - C: 1 (left), 1 (right) - O: 3 (left), 3 (right) - Na: 2 (left), 2 (right) - S: 1 (left), 1 (right)

The equation is now balanced.

I hope this helps! Let me know if there's anything else I can assist you with.