Question

У дві пробірки наливаєм розчин пероксиду водню. В одну із пробірок додаємо декілька кришталиків Манган (4)Оксиду МПО2 і опускаємо в пробірку запалену скіпку що спостерігається? Напишіть рівняння розкладу пероксиду водню під дією каталізатору? І що відбувається в другій пробірці?

Answer 1

Reaction with Hydrogen Peroxide and Manganese(IV) Oxide

When manganese(IV) oxide (MnO2) is added to hydrogen peroxide (H2O2) in a test tube and a glowing splint is inserted, the splint will reignite due to the release of oxygen gas. This reaction can be represented by the following equation:

Equation for the decomposition of hydrogen peroxide: ``` 2 H2O2 (aq) → 2 H2O (l) + O2 (g) ```

The manganese(IV) oxide acts as a catalyst in this reaction, speeding up the decomposition of hydrogen peroxide into water and oxygen. The manganese(IV) oxide provides a surface for the reaction to occur more easily, without being consumed in the process.

Reaction in the Second Test Tube

In the second test tube, where only hydrogen peroxide is present, the hydrogen peroxide will not undergo any noticeable reaction without the presence of a catalyst. The solution will remain unchanged.

In summary, the addition of manganese(IV) oxide to hydrogen peroxide causes the decomposition of hydrogen peroxide into water and oxygen, while the hydrogen peroxide in the second test tube remains unchanged in the absence of a catalyst.

I hope this explanation helps! If you have any more questions or need further clarification, feel free to ask.