Question

Дам 30б Выполните следующие задания: Вычислите относительные молекулярные массы: Zn(OH)2, CaCl2, Ba3(PO4)2 Укажите валентность в соединениях: CF4, V2O5 , ZnCl2, CuO, Cu2O, Mg3P2 Расставьте коэффициенты в уравнениях химических реакций: SO2 + O2 --- SO3 Zn + HCl --- ZnCl2 + H2 Al + HCl ---- AlCl3 + H2 NaOH + SO3 --- Na2SO4 + H2O NaHCO3 --- Na2CO3 + CO2 + H2O

Answer 1

Ответ:

Объяснение:

1) Mr(Zn(OH)2) =65+16*2+1*2 =99

Mr(CaCl2) = 40 + 35,5*2 =111

Mr(Ba3(PO4)2 = 137*3 + 31*2 + 16*8 = 601

2) C(IV)F(I),   V(V)O(II),  Zn(II)Cl(I),  Cu(II)O(II),  Cu(I)O(II),  Mg(II)P(III)

3) 2SO2 + O2 = 2SO3

Zn + 2HCl = ZnCl2 + H2

2Al + 6HCl = 2AlCl3 + 3H2

2NaOH + SO3 = Na2SO4 + H2O

2NaHCO3 = Na2CO3 + CO2 + H2O

Answer 2

Calculating Relative Molecular Masses:

To calculate the relative molecular masses of the given compounds, we need to determine the atomic masses of the elements involved and sum them up according to the molecular formula.

1. Zn(OH)2: - Atomic mass of Zn = 65.38 g/mol - Atomic mass of O = 16.00 g/mol - Atomic mass of H = 1.01 g/mol - Relative molecular mass of Zn(OH)2 = (65.38 * 1) + (16.00 * 2) + (1.01 * 2) = 97.38 g/mol [[1]]

2. CaCl2: - Atomic mass of Ca = 40.08 g/mol - Atomic mass of Cl = 35.45 g/mol - Relative molecular mass of CaCl2 = (40.08 * 1) + (35.45 * 2) = 110.98 g/mol [[2]]

3. Ba3(PO4)2: - Atomic mass of Ba = 137.33 g/mol - Atomic mass of P = 30.97 g/mol - Atomic mass of O = 16.00 g/mol - Relative molecular mass of Ba3(PO4)2 = (137.33 * 3) + (30.97 * 2) + (16.00 * 8) = 601.92 g/mol [[3]]

Valency in Compounds:

Valency refers to the combining capacity of an element in a compound. It indicates the number of electrons an atom can gain, lose, or share to form chemical bonds.

1. CF4: - Carbon (C) has a valency of 4. - Fluorine (F) has a valency of 1. - Therefore, the valency in CF4 is 4 for carbon and 1 for fluorine.

2. V2O5: - Vanadium (V) has variable valencies, but in V2O5, it has a valency of 5. - Oxygen (O) has a valency of 2. - Therefore, the valency in V2O5 is 5 for vanadium and 2 for oxygen.

3. ZnCl2: - Zinc (Zn) has a valency of 2. - Chlorine (Cl) has a valency of 1. - Therefore, the valency in ZnCl2 is 2 for zinc and 1 for chlorine.

4. CuO: - Copper (Cu) has a valency of 2. - Oxygen (O) has a valency of 2. - Therefore, the valency in CuO is 2 for copper and 2 for oxygen.

5. Cu2O: - Copper (Cu) has a valency of 2. - Oxygen (O) has a valency of 2. - Therefore, the valency in Cu2O is 2 for copper and 2 for oxygen.

6. Mg3P2: - Magnesium (Mg) has a valency of 2. - Phosphorus (P) has a valency of 3. - Therefore, the valency in Mg3P2 is 2 for magnesium and 3 for phosphorus.

Balancing Chemical Equations:

To balance chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. We can achieve this by adjusting the coefficients in front of the chemical formulas.

1. SO2 + O2 → SO3: - The equation is already balanced.

2. Zn + HCl → ZnCl2 + H2: - The balanced equation is: Zn + 2HCl → ZnCl2 + H2.

3. Al + HCl → AlCl3 + H2: - The balanced equation is: 2Al + 6HCl → 2AlCl3 + 3H2.

4. NaOH + SO3 → Na2SO4 + H2O: - The balanced equation is: 2NaOH + SO3 → Na2SO4 + H2O.

5. NaHCO3 → Na2CO3 + CO2 + H2O: - The balanced equation is: 2NaHCO3 → Na2CO3 + CO2 + H2O.

Please let me know if you need any further assistance!