Question

Газ С2Н4 об"ємом 1,12л яку має масу Дуже потрібно!!!!

Answer 1

Ответ:

ответ смотри во вложении

Answer 2

Calculating the Mass of C2H4 Gas with a Volume of 1.12L

To calculate the mass of a gas, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature in Kelvin

We can rearrange the equation to solve for the number of moles (n):

n = PV / RT

Given: - Volume (V) = 1.12L - Assume standard temperature and pressure (STP): - Pressure (P) = 1 atm - Temperature (T) = 273.15 K - Ideal gas constant (R) = 0.0821 L·atm/(K·mol)

Let's calculate the number of moles of C2H4 gas using the provided volume and STP.

Calculating the Number of Moles: ``` V = 1.12L P = 1 atm T = 273.15 K R = 0.0821 L·atm/(K·mol)

n = (1 atm * 1.12L) / (0.0821 L·atm/(K·mol) * 273.15 K) ``` n = (1 * 1.12) / (0.0821 * 273.15) n ≈ 0.046 moles

Now, to calculate the mass of C2H4 gas, we need to know the molar mass of C2H4.

The molar mass of C2H4 (ethylene) can be calculated as: - Carbon (C) molar mass = 12.01 g/mol - Hydrogen (H) molar mass = 1.008 g/mol

Molar mass of C2H4 = 2(C) + 4(H) = 2(12.01) + 4(1.008) ≈ 28.05 g/mol

Calculating the Mass of C2H4 Gas: ``` Mass = number of moles * molar mass Mass = 0.046 moles * 28.05 g/mol ``` Mass ≈ 1.29 grams

So, the gas C2H4 with a volume of 1.12L has a mass of approximately 1.29 grams.