Question

какую массу чистого железа можно получить из 250т руды с массовой долей пирита FeSдва 0.7 , если выход продукта реакции составляет 82%?

Answer 1

FeS2----t(>1000 C)--> Fe + 2S

m(FeS2)чистого=250*0,7=175т

n(FeS2)=175000/120= 1.45 кМоль

 n(Fe)=n(FeS2)=1.45 кМоль

m(Fe)=1.45кМоль*56*0.82= 66.5 т

Answer 2

Calculating the Mass of Pure Iron Obtained from the Ore

To calculate the mass of pure iron that can be obtained from 250 tons of ore with a mass fraction of pyrite (FeS2) of 0.7 and a reaction product yield of 82%, we can use the following steps:

1. Calculate the mass of iron in the ore: - The mass fraction of pyrite (FeS2) is 0.7, which means the mass fraction of iron (Fe) in pyrite is 1 - 0.7 = 0.3. - We can calculate the mass of iron in the ore by multiplying the total mass of the ore by the mass fraction of iron in pyrite.

The mass of iron in the ore = 250 tons × 0.3 = 75 tons [[1]].

2. Calculate the mass of pure iron obtained: - Since the reaction product yield is 82%, we can calculate the mass of pure iron obtained by multiplying the mass of iron in the ore by the yield percentage.

The mass of pure iron obtained = 75 tons × 0.82 = 61.5 tons.

Therefore, from 250 tons of ore with a mass fraction of pyrite of 0.7 and a reaction product yield of 82%, it is possible to obtain approximately 61.5 tons of pure iron.