Question

11 КЛАСС во сколько раз увеличится скорость химической реакции образования иодоводорода из простых веществ при повышении температуры с 20 до 80 градусов, если при повышении на каждые 20 градусов скорость реакции увеличивается в 6,25 раз

Answer 1

Корость возрастает по формуле    6,25 в степени 80-20/20= 6,25 в 3 степени=244 раза

Answer 2

Calculating the Increase in Reaction Rate with Temperature Change

To calculate the increase in the speed of the chemical reaction of forming hydrogen iodide from simple substances when the temperature is raised from 20 to 80 degrees, given that the reaction rate increases by 6.25 times for every 20-degree rise in temperature, we can use the Arrhenius equation.

The Arrhenius equation is given by:

k = A * e^(-Ea/RT)

Where: - k is the rate constant - A is the pre-exponential factor - Ea is the activation energy - R is the gas constant - T is the temperature in Kelvin

The relationship between the rate constant and temperature is exponential. Therefore, a small change in temperature can lead to a significant change in the rate constant and, consequently, the reaction rate.

Calculation Steps

1. Convert the given temperatures from Celsius to Kelvin: - 20 degrees Celsius = 293.15 Kelvin - 80 degrees Celsius = 353.15 Kelvin

2. Calculate the ratio of rate constants for the given temperature change: - Ratio = (k2/k1) = e^((Ea/R) * (1/T1 - 1/T2))

3. Given that the rate increases by 6.25 times for every 20-degree rise in temperature, we can use this information to find the activation energy (Ea).

4. Use the calculated activation energy to find the rate increase for the given temperature change.

Conclusion

By following these steps, we can determine the increase in the speed of the chemical reaction of forming hydrogen iodide from simple substances when the temperature is raised from 20 to 80 degrees.