Question

10. Розставте коефіцієнти в схемах хімічних реакцій : б) Са + H3PO4 г) К+ a) Cu + O2 → B) H2O → H2 + Cu2O 02 O2 → Са3(PO4)2 + Н2О - КОН + Н2 Н2​

Answer 1

a) 2Cu + O2 → 2CuO

б) 3Са + 2H3PO4 --> Ca3(PO4)2 + 3H2

в) 2H2O → 2H2 + O2

г) 2K + 2H2O --> 2KOH + H2

Answer 2

Coefficients in Chemical Reactions:

a) Cu + O2 → Cu2O b) Ca + H3PO4 → Ca3(PO4)2 + H2O c) KOH + H2SO4 → K2SO4 + H2O

Please note that the coefficients in chemical reactions represent the relative amounts of each substance involved in the reaction. These coefficients are used to balance the equation and ensure that the law of conservation of mass is obeyed.

Let's go through each reaction and determine the coefficients:

a) Cu + O2 → Cu2O In this reaction, we have copper (Cu) reacting with oxygen (O2) to form copper(I) oxide (Cu2O). To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Therefore, the coefficients are: 2Cu + O2 → 2Cu2O [[1]]

b) Ca + H3PO4 → Ca3(PO4)2 + H2O In this reaction, we have calcium (Ca) reacting with phosphoric acid (H3PO4) to form calcium phosphate (Ca3(PO4)2) and water (H2O). To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Therefore, the coefficients are: 3Ca + 2H3PO4 → Ca3(PO4)2 + 3H2O [[2]]

c) KOH + H2SO4 → K2SO4 + H2O In this reaction, we have potassium hydroxide (KOH) reacting with sulfuric acid (H2SO4) to form potassium sulfate (K2SO4) and water (H2O). To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Therefore, the coefficients are: 2KOH + H2SO4 → K2SO4 + 2H2O [[3]]

I hope this helps! Let me know if you have any further questions.