Question

50 БАЛЛОВ СРОЧНО НАДО!!!! Обчисліть масу натрій етаноату, який утвориться в разі дії надлишку металічного натрію на 150 г оцтової кислоти, що містить 10 % домішок?

Answer 1

Ответ:

Объяснение:

Спочатку знайдемо кількість чистої оцтової кислоти в 150 г розчину:

150 г * 0.9 = 135 г

Молярна маса оцтової кислоти CH3COOH: 60 г/моль

Кількість молей CH3COOH:

135 г / 60 г/моль = 2.25 моль

За рівнянням реакції між CH3COOH і Na:

CH3COOH + Na → CH3COONa + 1/2H2

1 моль CH3COOH взаємодіє з 1 моль Na. Тому 2.25 моль CH3COOH взаємодіє з 2.25 моль Na.

Молярна маса NaCH3COO: 82 г/моль

Маса NaCH3COO, що утвориться:

2.25 моль * 82 г/моль = 184.5 г

Отже, маса натрій етаноату, який утвориться, становить 184.5 г.

Answer 2

To calculate the mass of sodium ethanoate formed when an excess of metallic sodium reacts with 150 g of acetic acid containing 10% impurities, we need to consider the balanced chemical equation for the reaction and the molar masses of the compounds involved.

The balanced chemical equation for the reaction between sodium and acetic acid is:

2CH3COOH + 2Na -> 2CH3COONa + H2

From the equation, we can see that 2 moles of acetic acid react with 2 moles of sodium to produce 2 moles of sodium ethanoate.

To calculate the mass of sodium ethanoate, we can follow these steps:

1. Calculate the number of moles of acetic acid: - Given mass of acetic acid = 150 g - Molar mass of acetic acid (CH3COOH) = 60.05 g/mol - Number of moles of acetic acid = mass/molar mass = 150 g / 60.05 g/mol

2. Calculate the number of moles of sodium ethanoate: - From the balanced equation, we know that 2 moles of acetic acid react to form 2 moles of sodium ethanoate. - Therefore, the number of moles of sodium ethanoate is the same as the number of moles of acetic acid.

3. Calculate the mass of sodium ethanoate: - Given that the molar mass of sodium ethanoate (CH3COONa) is 82.03 g/mol, we can calculate the mass using the number of moles obtained in step 2: - Mass of sodium ethanoate = number of moles * molar mass = number of moles * 82.03 g/mol

Now, let's calculate the mass of sodium ethanoate using the given information:

1. Calculate the number of moles of acetic acid: - Number of moles of acetic acid = 150 g / 60.05 g/mol = 2.498 moles

2. Calculate the number of moles of sodium ethanoate: - Number of moles of sodium ethanoate = 2.498 moles

3. Calculate the mass of sodium ethanoate: - Mass of sodium ethanoate = 2.498 moles * 82.03 g/mol = 205.02 g

Therefore, the mass of sodium ethanoate formed in the reaction is approximately 205.02 grams.

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