Question

16. Складіть рівняння окисно-відновної реакції за схемою, використавши метод електронного балансу. Вкажіть процес окиснення та відновлення. Zn + H2SO4 (конц.) → ZnSO4 + S + H2O

Answer 1

Ответ:  3Zn+4H2SO4=3ZnSO4+S+4H2O

              в-ль   Zn - 2e-->Zn       3     о-ние

                                           6

              о-ль   S + 6e---> S        1     в-ние

     

Объяснение:

Answer 2

Balancing the Redox Reaction:

To balance the redox reaction using the electron balance method, we need to assign oxidation numbers to each element in the reaction and then balance the number of electrons transferred.

The given reaction is: Zn + H2SO4 (conc.) → ZnSO4 + S + H2O

1. Assigning oxidation numbers: - The oxidation number of Zn is 0 since it is an uncombined element. - The oxidation number of H in H2SO4 is +1. - The oxidation number of S in H2SO4 is +6. - The oxidation number of O in H2SO4 is -2. - The oxidation number of Zn in ZnSO4 is +2. - The oxidation number of S in ZnSO4 is +6. - The oxidation number of O in ZnSO4 is -2. - The oxidation number of S in S is 0. - The oxidation number of H in H2O is +1. - The oxidation number of O in H2O is -2.

2. Identifying the oxidation and reduction half-reactions: - Oxidation half-reaction: Zn → ZnSO4 - Reduction half-reaction: H2SO4 → S + H2O

3. Balancing the number of electrons transferred: - In the oxidation half-reaction, Zn loses 2 electrons. - In the reduction half-reaction, S gains 2 electrons.

4. Balancing the half-reactions: - Oxidation half-reaction: Zn → ZnSO4 + 2e- - Reduction half-reaction: H2SO4 + 2e- → S + H2O

5. Balancing the overall reaction: - Multiply the oxidation half-reaction by 1 and the reduction half-reaction by 2 to balance the number of electrons transferred. - The balanced overall reaction is: Zn + 2H2SO4 (conc.) → ZnSO4 + 2S + 2H2O

Oxidation and Reduction Processes:

In the given reaction, the oxidation process occurs at the Zn atom, which loses 2 electrons and forms ZnSO4. The oxidation state of Zn changes from 0 to +2. Therefore, Zn undergoes oxidation.

The reduction process occurs at the S atom in H2SO4, which gains 2 electrons and forms S. The oxidation state of S changes from +6 to 0. Therefore, S undergoes reduction.

Overall, the reaction involves the oxidation of Zn and the reduction of S.

Note: The information provided above is based on search results and the electron balance method for balancing redox reactions.