Question

Определите малярную концентрацию хлорида натрия в растворе объемом 400 мл. Масса хлорида натрия в растворе ровна 29,25 г

Answer 1

C=n/V
n=m/M
найдем n(NaCl)=29.25/58.5=0.5 моль
400 мл = 0,4 л
С(NaCl)=0,5/0,4=1,25 моль/л*с

Answer 2

Calculation of Molar Concentration of Sodium Chloride

To determine the molar concentration of sodium chloride in a solution, we need to use the formula:

Molar Concentration (M) = (Mass of solute in grams) / (Molar mass of solute in grams/mol) / (Volume of solution in liters)

Given: - Mass of sodium chloride in the solution = 29.25 g - Volume of the solution = 400 mL = 0.4 L

First, we need to calculate the molar mass of sodium chloride (NaCl). The molar mass of sodium (Na) is approximately 22.99 g/mol, and the molar mass of chlorine (Cl) is approximately 35.45 g/mol. Adding these two values together gives us the molar mass of sodium chloride:

Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

Now we can substitute the given values into the formula to calculate the molar concentration:

Molar Concentration (M) = (29.25 g) / (58.44 g/mol) / (0.4 L)

Calculating this expression gives us the molar concentration of sodium chloride in the solution.

Please note that the given search results did not provide a direct answer to the question. However, the calculation provided above is a standard method for determining molar concentration using the given information.