Question

Умоляю побыстрее. к 200 г 30% раствора карбоната натрия прилили раствор серной кислоты. сколько оксида углерода 4 образовалось при этом

Answer 1

1)Для начала найдем массу карбоната натрия (чист.) - 200*30/100=60г
2)подставим эту массу в ур-е и делаем расчеты по ур-ю, решаем пропорцией; в итоге получим х=60*22,4/106=12,6л

Answer 2

Calculating the Amount of Carbon Dioxide Formed

To calculate the amount of carbon dioxide formed when a 30% solution of sodium carbonate is mixed with sulfuric acid, we can use the following chemical equation:

Na2CO3 + H2SO4 → Na2SO4 + H2O + CO2

According to the equation, 1 mole of sodium carbonate reacts with 1 mole of sulfuric acid to produce 1 mole of carbon dioxide.

Calculation Steps

1. Calculate the moles of sodium carbonate (Na2CO3): - The given amount is 200 g of a 30% solution of sodium carbonate. - First, calculate the mass of sodium carbonate in the solution: - 30% of 200 g = 0.3 * 200 g = 60 g - Next, convert the mass of sodium carbonate to moles using its molar mass: - Molar mass of Na2CO3 = 22.99*2 + 12.01 + 16.00*3 = 105.99 g/mol - Moles of Na2CO3 = 60 g / 105.99 g/mol

2. Calculate the moles of carbon dioxide (CO2) formed: - According to the balanced chemical equation, 1 mole of Na2CO3 produces 1 mole of CO2.

3. Final Calculation: - The moles of carbon dioxide formed will be the same as the moles of sodium carbonate used.

Conclusion

Based on the given information, the amount of carbon dioxide formed when 200 g of a 30% solution of sodium carbonate is mixed with sulfuric acid is equal to the moles of sodium carbonate used in the reaction.

Please note that the exact numerical value of the moles of carbon dioxide formed would depend on the specific amount of sodium carbonate used, which is calculated to be 60 g in this case.